Answer:
Step-by-step explanation:
LHS = Sin² ∅ + Sin² ∅*tan² ∅
= Sin² ∅ [1 + tan² ∅ ] {Sec² ∅ - tan² ∅ = 1}
= Sin² ∅ *Sec² ∅
= Sin² ∅ * 
= Sin² ∅ /Cos² ∅
= tan² ∅ = RHS
X² + 3x = 10
Convert to standard form.
x² + 3x - 10 = 0
factor x² = x * x
factor -10 = 5 * -2
(x + 5) (x - 2) = 0
x(x -2) + 5(x-2) = 0
x² - 2x + 5x - 10 = 0
x² + 3x - 10 = 0
x + 5 = 0 x² + 3x = 10
x = -5 -5² + 3(-5) = 10
25 - 15 = 10
10 = 10
x - 2 = 0 x² + 3x = 10
x = 2 2² + 3(2) = 10
4 + 6 = 10
10 = 10
A negative times a negative is a positive. I am not sure if that's the question, but hopefully that helps if it was.
Answer:
Step-by-step explanation:
Answer:
All the exponents in the algebraic expression must be non-negative integers in order for the algebraic expression to be a polynomial. As a general rule of thumb if an algebraic expression has a radical in it then it isn't a polynomial
so no its not.
