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2 years ago

Someone please help me. 10=7x+4-4x

Mathematics

2 answers:

MrMuchimi2 years ago

7 0

X=2. First, you would combine like terms, making the expression state 3x+4=10. Then, subtract 4 from both sides. 3x=6. Divide by 3 on both sides to isolate x. x=2

kakasveta [241]2 years ago

4 0

Answer:

x=2

Step-by-step explanation:

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Jackie wants to buy some hair ties that each cost $5.95, and a lip balm that costs $2.15. She has $20. Use the guess, check, and

Sonja [21]

Answer:

She can buy 3 hair ties

Step-by-step explanation:

5.95x3 =17.85 +2.15 = 20 on the dot

4 0

2 years ago

You roll a six-sided die. Find the probability of each of the following scenarios

romanna [79]

Answer:

a) $1/2$

b) $5/6$

c) $2/3$

Step-by-step explanation:

Rolling a number greater than 3 means you can roll a 4, 5, or 6, which contains rolling a 6. So, the probability is $(1+1+1)/6=3/6=\boxed{1/2}$

Rolling a number less than 5 means you can roll a 1, 2, 3, or 4, but because you could also roll an even number, so you could also roll a 6.

So, the probability is $(1+1+1+1+1)/6=\boxed{5/6}$

Rolling a 4 or an odd number means you can roll a 1, 3, 5, or 4. So, the probability is $(1+1+1+1)/6=4/6=\boxed{2/3}$

6 0

1 year ago

2. It costs Edgar $2.65 one way to ride the bus to work. He uses the bus to go to and from work four days per week. He buys a bo

Maurinko [17]

$27

2.65 x 2 (since he has to go both to and from work each day) = $5.30
Add the daily cost of the water bottle (1.45) to make his total cost for one day, which is 6.75
Multiply this number by 4 (because he goes 4 days a week) to get $27 for one week.

6 0

2 years ago

Find the area of the region that lies inside the first curve and outside the second curve. r = 6 − 6 sin θ, r = 6

yan [13]

Each curve completes one loop over the interval $0\le t\le2\pi$ . Find the intersections of the curves within this interval.

$6-6\sin\theta=6\implies 1-\sin\theta=1\implies \sin\theta=0\implies \theta=0,\theta=\pi$

The region of interest has an area given by the double integral

$\displaystyle\int_\pi^{2\pi}\int_6^{6-6\sin\theta}r\,\mathrm dr\,\mathrm d\theta$

equivalent to the single integral

$\displaystyle\frac12\int_\pi^{2\pi}\bigg((6-6\sin\theta)^2-6^2\bigg)\,\mathrm d\theta$

which evaluates to $9\pi+72$ .

8 0

2 years ago

Evaluate $\dfrac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}$.

Pavlova-9 [17]

<h3>Answer: 4</h3>

========================================================

Work Shown:

$\frac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}\\\\\frac{2\sqrt{36*2}}{\sqrt{4*2}+\sqrt{2}}\\\\\frac{2\sqrt{36}*\sqrt{2}}{\sqrt{4}*\sqrt{2}+\sqrt{2}}\\\\\frac{2*6*\sqrt{2}}{2*\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{2\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{3\sqrt{2}}\\\\\frac{12}{3}\\\\4$

Note in step 2, I factored each number in the square root to pull out the largest perfect square factor. From there, I used the rule that $\sqrt{A*B} = \sqrt{A}*\sqrt{B}$ to break up the roots.

8 0

1 year ago

Someone please help me. 10=7x+4-4x​

Someone please help me. 10=7x+4-4x