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DiKsa [7]
3 years ago
11

Qué fuerza necesitamos para levantar un peso de 300kg con una polea fija o simple​

Mathematics
1 answer:
Helga [31]3 years ago
6 0
Ndnsnsnsksk. sksjsjsiia, skaakksjsksjjsks.
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Brittany is selling car magnets. She purchased a them for $7.50 each and marks up the price by 30%. How much is Brittany plannin
-Dominant- [34]
Hello! So Brittany plans to sell car magnets that she purchased at $7.50 and mark them up by 30%. To find the new price, we can multiply 7.50 * 1.30. When multiplied, it gives us 9.75. Brittany is planning to charge $9.75 for the car magnets.
6 0
3 years ago
Solve for x.<br><br> 4(x−214)=−3.7<br><br> Enter your answer as a decimal in the box.<br><br> x =
andre [41]
X = 213.075
First you have to get rid of the 4 and since it’s multiplying you to the opposite and that’s dividing.
-3.7 divided by 4 = -0.925
X - 214 = -0. 925
Then you add 214 to -0.925 and get 213.075
7 0
3 years ago
Kalynn plans to cut an 8 foot sandwich into pieces that are 1/2 foot long. How many pieces of the sandwich will she have after i
Kazeer [188]

Answer: 16

You divide 8 by 1/2 and you get 16 pieces

3 0
3 years ago
Roxanne is comparing the monthly payments for a new car at two different car dealerships.
andreyandreev [35.5K]

9514 1404 393

Answer:

  A: $563.39

  B: $567.84

Step-by-step explanation:

The attached shows the formula. The graphing calculator evaluates it for the different car choices.

The monthly payment for the car from Dealership A is $563.39.

The monthly payment for the car from Dealership B is $567.84.

5 0
3 years ago
This shape is made using three semicircles The smaller semicircle have diameters of 10cm Calculate the shaded area Take 3.142 an
CaHeK987 [17]

Answer:

The shaded area is 314.2 cm²

Step-by-step explanation:

Here we have the diameter, d₁ of the smaller semicircles as 10 cm

We note that the larger semicircle is subtended (bounded) by the two smaller semicircles;

1 shaded small semicircle and the other is blank

Therefore, the diameter, d₂ of the large semicircle = 10 + 10 = 20 cm

Also the area of the shaded figure consists of the removal of one small semicircle and the addition of the other semicircle to the area of the larger semicircle such that the area of the shaded figure is as follows

Shaded area of figure = π·d₂²/4 + π·d₁²/4 - π·d₁²/4 = π·d₂²/4 = π×20²/4 = 100×3.142 = 314.2 cm²

Shaded area = 314.2 cm².

6 0
3 years ago
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