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DiKsa [7]
3 years ago
11

Qué fuerza necesitamos para levantar un peso de 300kg con una polea fija o simple​

Mathematics
1 answer:
Helga [31]3 years ago
6 0
Ndnsnsnsksk. sksjsjsiia, skaakksjsksjjsks.
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Round 3.255 to the nearest hundredth.
Oduvanchick [21]

Answer:

3.26

Step-by-step explanation:

if there is a five you round it up too 3.26

3 0
4 years ago
Help with 19,20,21,23 please i don't understand geometry at all
Murrr4er [49]
19.  What you know is that HK+KJ = HJ.  If HJ = 25, the sum of the two equations will equal this length.  

x-5+5x-12=25  First, combine your like terms.  You will end up with 6x-17=25.  Add the opposite of -17 to both sides.  6x = 42  Divide both sides by 6.  x = 7.  Substitute x=7 for your original expression of x-5, 7-5=2

20.  (5x-6)/2 = x+6  Multiply each side by 2.  5x-6 = 2x +12  Add 6 to each side 5x = 2x + 18 then subtract 2x from both sides as well.  3x = 18 Finally divide each side by 3.  x=6   To find the length of the remaining segment, substitute this value into (5x-6)/2.  This results in each side equaling a distance of 12.

21.  On the number line, the distance of FG is 16 units.  If the distance of FP is 1/4 of FG, you would simply divide 16 by 4.  The distance of FP is 4 and P lies at 8 on your number line.

23. The distance of SP is x+4 and ST=4x.  Since P is the midpoint, you only have one half of the line as x+4, if you were to double it, you would find that 2x+8 = 4x.  Balance and solve for x, subtract 2x from both sides. 8=2x  Divide each side by 4, 8/4 = 4x/4 resulting in x=2.  If ST equals 4x, substitute and solve, 4(2) = 8
8 0
3 years ago
Which statement is a correct interpretation of the vertical line test?
bulgar [2K]

Answer:

A and D

because those are the correct ones :)

4 0
4 years ago
X^3 plus 6x squared plus 3x minus−10x plus 5
Iteru [2.4K]
 the answer is X^3+6x<span>^2-7x+5

</span>
7 0
3 years ago
HELP ME PLEASE IVE BEEN STRUGGLING WITH THIS FOR SO LONG
Ber [7]

Answer:

<h2>m∠ACE = 90°</h2>

Step-by-step explanation:

Figure Interpretation:

m∠CBA + m∠CDE = 180

m∠BCA = (180-m∠CBA)/2

m∠DCE = (180-m∠CDE)/2

=======================

Then

m∠BCA + m∠DCE = (180-m∠CBA)/2 + (180-m∠CDE)/2

                                = [360-(m∠CBA+m∠CDE)]/2

                                = [360 - 180]/2

                                = 90

finally,

m∠ACE= 180 - (m∠BCA + m∠DCE)

             = 180 - 90

             = 90

8 0
2 years ago
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