The price of 1 hat is $ 5 and price of 1 t-shirt is $ 8
<em><u>Solution:</u></em>
Let "s" be the price of 1 shirt
Let "h" be the price of 1 hat
<em><u>Given that Jones buys 7 t-shirts and 6 hats for $86</u></em>
Therefore, we can frame a equation as:
price of 1 shirt x 7 + price of 1 hat x 6 = 86
7s + 6h = 86 ------ eqn 1
<em><u>Also given that The price of each t shirt is $3 more than the price of each hat</u></em>
price of 1 shirt = 3 + price of 1 hat
s = 3 + h -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Substitute eqn 2 in eqn 1
7( 3 + h ) + 6h = 86
21 + 7h + 6h = 86
21 + 13h = 86
13h = 86 - 21
13h = 65
<h3>h = 5</h3>
From eqn 2,
s = 3 + h = 3 + 5 = 8
<h3>s = 8</h3>
Thus price of 1 hat is $ 5 and price of 1 t-shirt is $ 8
Answer: the cost of 1 one-inch binder is $4
the cost of 1 three-inch binder is $7
Step-by-step explanation:
Let x represent the cost of 1 one-inch binder.
Let x represent the cost of 1 three-inch binder.
Jesse selected 3 one-inch binders and 3 two-inch binders, which cost a total of $33. This means that
3x + 3y = 33 - - - - - - - - - - 1
Luann selected 2 one-inch binders and 1 two-inch binder, which cost a total of $15. This means that
2x + y = 15 - - - - - - - - - - - 2
Multiplying equation 1 by 2 and equation 2 by 3, it becomes
6x + 6y = 66
6x + 3y = 45
Subtracting, it becomes
3y = 21
y = 21/3 = 7
Substituting y = 7 into equation 2, it becomes
2x + 7 = 15
2x = 15 - 7 = 8
x = 8/2 = 4
Answer:
-(13 w + 7)
Step-by-step explanation:
Simplify the following:
-6 w - 8 + 1 - 7 w
Grouping like terms, -6 w - 8 + 1 - 7 w = (-6 w - 7 w) + (1 - 8):
(-6 w - 7 w) + (1 - 8)
-6 w - 7 w = -13 w:
-13 w + (1 - 8)
-8 + 1 = -7:
-13 w + -7
Factor -1 out of -13 w - 7:
Answer: -(13 w + 7)
