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Harman [31]
2 years ago
8

Last one, Estimate the perimeter and the area of the shaded figure

Mathematics
1 answer:
myrzilka [38]2 years ago
8 0

Answer:

13 and a half

Step-by-step explanation:

I just counted the squares bro

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PLEASE HELP ILL GIVE BRAINLIEST
dusya [7]

1)

(-2+\sqrt{-5})^2\implies (-2+\sqrt{-1\cdot 5})^2\implies (-2+\sqrt{-1}\sqrt{5})^2\implies (-2+i\sqrt{5})^2 \\\\\\ (-2+i\sqrt{5})(-2+i\sqrt{5})\implies +4-2i\sqrt{5}-2i\sqrt{5}+(i\sqrt{5})^2 \\\\\\ 4-4i\sqrt{5}+[i^2(\sqrt{5})^2]\implies 4-4i\sqrt{5}+[-1\cdot 5] \\\\\\ 4-4i\sqrt{5}-5\implies -1-4i\sqrt{5}

3)

let's recall that the conjugate of any pair a + b is simply the same pair with a different sign, namely a - b and the reverse is also true, let's also recall that i² = -1.

\cfrac{6-7i}{1-2i}\implies \stackrel{\textit{multiplying both sides by the denominator's conjugate}}{\cfrac{6-7i}{1-2i}\cdot \cfrac{1+2i}{1+2i}\implies \cfrac{(6-7i)(1+2i)}{\underset{\textit{difference of squares}}{(1-2i)(1+2i)}}} \\\\\\ \cfrac{(6-7i)(1+2i)}{1^2-(2i)^2}\implies \cfrac{6-12i-7i-14i^2}{1-(2^2i^2)}\implies \cfrac{6-19i-14(-1)}{1-[4(-1)]} \\\\\\ \cfrac{6-19i+14}{1-(-4)}\implies \cfrac{20-19i}{1+4}\implies \cfrac{20-19i}{5}\implies \cfrac{20}{5}-\cfrac{19i}{5}\implies 4-\cfrac{19i}{5}

7 0
3 years ago
Read 2 more answers
2) two florist purchased flower bouquets and vases at the same store. The first florist bought 2 flower bouquets and two vases f
Feliz [49]
Let
b---------> <span>the cost of one flower bouquet
</span>v-------->  <span>the cost of one vase.

we know that
2b+2v=12.50-----> </span>Multiplied by -1------------->-2b-2v=-12.50
8b+2v=29---------------------------------------------> 8b+2v=29
           I add the two equations                    ------------------------
                                                                        6b=16.50
b=2.75
2*2.75+2*v=12.50---------------> v=(12.50-5.5)/2---------> v=3.5

the answer is
the cost of one flower bouquet is $2.75
the cost of one vase is $3.5

7 0
3 years ago
I need help ASAP
Dima020 [189]

Answer:

20

Step-by-step explanation:

x/2+15=25

x/2=10

x=20

Please mark as Brainliest! :)

Have a nice day.

3 0
3 years ago
Read 2 more answers
What should the IUPAC name for a binary covalent compound lack? prefixes Roman numerals an -ide ending the name of a nonmetal.​
vitfil [10]

The  IUPAC name for a binary covalent compound lack prefixes such as mono, di, tri tetra etc.

A binary compound is a compound that is composed of only two elements. Many binary compounds could be made up of a metal and a nonmetal or even two nonmetals as the case may be. Examples of binary compounds include; SO2, NaH, K2S etc.

We must note that a binary covalent compound uses Roman numerals to indicate the oxidation state of the central atom in the compound. For instance, SO2 is called Sulfur IV oxide.

Hence, the  IUPAC name for a binary covalent compound lack prefixes such as mono, di, tri tetra etc.

Lear more about IUPAC: brainly.com/question/11587934

5 0
2 years ago
Mrs delles spent 120$ on a bag that was discounted 25%, what was the original price.
luda_lava [24]

Answer:

480

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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