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Black_prince [1.1K]

3 years ago

15

which one of the following proportions is true for the segments shown in the figure if lines a B and C are parallel to each othe

r

1 answer:

ycow [4]3 years ago

5 0

I believe it is A because line segment AC is equal to line segment BD, and AE and BF are also the same

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What is the value of the exponent when simplifying the following expression: 16^1/2•16^1/2

pantera1 [17]

Answer:

B.

Step-by-step explanation:

because they have the same base and it's a multiplication so you have to add the exponents

6 0

2 years ago

Read 2 more answers

What is the value of this expression when a = 2 and b = -3 ? a^3 - b^3 / 5

saveliy_v [14]

Answer:

13 2/5

Step-by-step explanation:

a = 2 and b = -3

so the question asks whats.... a^3 - b^3/5

First we plug in the values of a and b

(2)^3 - (-3)^3 /5

Now we solve the ones in paranthesis first

(2)^3 = 8 because 2×2×2 and

-(-3)^3 forget about the - outside the parenthesis so

(-3)^3 = (-27) because (-3)×(-3)×(-3)

now we put it back together

8 -(-27)/5

the two minus become plus so

8 + 27/5

Now we solve it like fractions

8 and 27/5

simplify

13 and 2/5

Hope that helps!

5 0

3 years ago

David rolls a fair dice 240 times. <br> How many times would David expect to roll a three?

jolli1 [7]

Answer:

40

Step-by-step explanation:

There are 6 numbers on an dice (1-6) Divide 240 by 6 and the reasonable amount of times to roll a 3 is 40 time

4 0

3 years ago

60 is whatpercent of 40

DiKsa [7]

<u>Answer:</u>

24

<u>Step-by-step explanation:</u>

Y is 60% of 40

Equation: Y = P% * X

<u>Solving our equation for Y</u>

Y = P% * X

Y = 60% * 40

<u>Converting percent to decimal:</u>

p = 60%/100 = 0.6

Y = 0.6 * 40

Y = 24

8 0

3 years ago

A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th

ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the average using the finite correction factor is:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

The information provided is:

$N=1500\\n=183\\\sigma=1.47\\\bar x=3.3$

The critical value of <em>z</em> for 95% confidence level is,

<em>z</em> = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

$=3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)$

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0

3 years ago