Answer:
The genotypes of the rooster and the chicken are homozygous and that of their offspring is heterozygous.
This case is called codominance, where the offspring receives an allele from each parent, from the rooster and the hen, because there is codominance, so neither allele is recessive and the phenotype of both alleles is expressed so the phenotype of the offspring is checkered.
We can say then that the chicken and the rooster have equal strength between their alleles. in the cases of codominance the laws of mendel do not apply.
The environment selected is favorable to ponies with longer legs.
Answer:
The correct answer is - 2n = 41 chromosomes.
Explanation:
It is given that the cat has a diploid chromosome number of 38 while the rabbit has a diploid number of 44 chromosomes and if they form a hybrid then their expected chromosome number in somatic cells would be -
Cat (2n=38) produces haploid gametes with 19 chromosomes (n-19).
Rabbit (2n=44) produces haploid gametes with 22 chromosomes(n=22)
19+22= 41 chromosomes in the particular hybrid as half number of chromosomes come from each parent.
