Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer:
x = 7
Step-by-step explanation:
2x+y=5
To put this in slope intercept form, you simply have to get y by itself on the left side of the equation.
2x+y=5
2x+y-2x=5-2x
y=-2x+5
Now, I had to switch the right side around like that, because slope intercept form is y=mx+b
Because you're subtracting 2x from 5, it becomes 5 added to -2x when it's put in the correct form.
y=-2x+5
You need to show the line put. If you show the line plot i may be able to answer. But F.Y.I. you are going to probably using proportions or need to multiply the hours she jogs in one day by the 5 days. Hope this helps.
