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3 years ago

6

-x(x-3)=8 solve for x. Express complex numbers in terms of i

1 answer:

My name is Ann [436]3 years ago

4 0

=(3\pm i\sqrt(23))/(2)

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The graph of which function will have a maximum and a y-intercept of 4?

rosijanka [135]

The y-intercept of the equation is the value of the variable y or in this case, f(x), when x is equated to zero. Out of all the choices presented in this item, if x is equated to zero, the first two terms will be equal to zero, leaving the third term only for the numerical value of f(x).

From the choices presented, the answer would be f(x) = -x2 + 2x + 4. Thus, the answer is the third choice, C.

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3 years ago

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At tire depot , a pair of new tires sells for $216. The managers special advertises the same tires at a rate of $380 for 4 tires

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A pair of tires is $216, so at that rate 4 tires would be $432. The managers special is $380 so $432-$380=$52 savings for 4. $52\4=$13 savings per tire.

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3 years ago

What is f(g(x)) if f(x)= 4x²+3x-4 and g(x)=2x

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3 years ago

A laundromat owner bought eleven new washing machines and eight new dryers. He paid the same amount for a dryer as for a washer.

Tatiana [17]

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550

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3 years ago

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a. Calculate the volume of the solid of revolution created by rotating the curve y = 3 + 3 exp(-5 x) about the x-axis, for x bet

miskamm [114]

Answer:

A) The volume of solid is 18π cubic unit.

B) The volume of sphere is $\dfrac{4}{3}\pi r^3$

a = -r , b = r , $f(x)=\sqrt{r^2-x^2}$ and $V=\dfrac{4}{3}\pi r^3$

Solution A)

The given curve, $y=3+3e^{-5x}$ rotate about x-axis between 2 to 4.

Please find attachment for solid figure or rotation.

Using disk method to find the volume rotation about x-axis

$V=\int_a^b\pi R^2dx$

where, a = 2, b= 4 , $R=y=3+3e^{-5x}$ and dx is thickness of disk.

$V=\int_2^4\pi (3+3e^{-5x})^2dx$

$V=9\pi\int_2^4(1+e^{-10x}+2e^{-5x})dx$

$V=9\pi(x-\dfrac{1}{10}e^{-10x}-\dfrac{2}{5}e^{-5x})|_2^4)$

$V=9\pi(4-\dfrac{1}{10}e^{-40}-\dfrac{2}{5}e^{-20}-2+\dfrac{1}{10}e^{-20}-\dfrac{2}{5}e^{-10}))$

$V=9\pi (2-0)$

$V=18\pi$

Hence, the volume of solid is 18π cubic unit

Solution B)

The equation of circle of radius r and centered at origin (0,0).

$x^2+y^2=r^2$

$y=\sqrt{r^2-x^2}$

The solid form is sphere of radius r.

Using disk method, to find volume of solid

$V=\int_a^b\pi R^2dx$

where, a = -r, b = r , $R=y=\sqrt{r^2-x^2}$ and dx is thickness of disk.

$V=\int_{-r}^r\pi (r^2-x^2)dx$

$V=\pi(r^2x-\dfrac{x^3}{3})|_{-r}^r$

$V=\pi(2r^3-\dfrac{2r^3}{3})$

$V=\dfrac{4}{3}\pi r^3$

Hence, the volume of sphere is $\dfrac{4}{3}\pi r^3$

4 0

4 years ago