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qwelly [4]
3 years ago
5

Katelyn’s biology test scores are shown below. Biology Test Scores A dot plot titled Biology Test Scores. The number line goes f

rom 80 to 90. There are 0 dots above 80, 81, and 82, 1 above 83, 2 above 84, 2 above 85, 2 above 86, 2 above 87, 0 above 88 and 89, and 1 above 90. Katelyn’s math test scores are shown below. Math Test Scores A dot plot titled Math Test Scores. The number line goes from 80 to 90. There are 0 dots above 80, 81, 82, and 83, 3 above 84, 2 above 85, 2 above 86, 3 above 87, 0 above 88, 89, and 90. Katelyn says that her biology test scores are much higher than her math test scores. Based on the shape of the data, which explains whether Katelyn is correct? Katelyn is correct because the score of 90 in biology is higher than any of her math scores. Katelyn is correct because her biology scores have a much wider range than her math scores. Katelyn is not correct because her score of 83 in biology is lower than any of her math scores. Katelyn is not correct because the middle of the data is about the same for each plot.

Mathematics
2 answers:
ipn [44]3 years ago
5 0

<em>Note: As you may have unintentionally missed to attach the figure. After a little research, I was able to find the figure. I have attached the figure, based on which I am solving which anyways would clear your concepts.</em>

Answer:

Katelyn is not correct because the middle of the data is about the same for each plot.

Step-by-step explanation:

<u>Calculating Mean for Math</u>

As the mean of a data set is the sum of the terms divided by the total number of terms. So, from the Math mapping data as shown in attached figure

                \mu=\frac{84+85+86+87}{4}

                    =\frac{171}{2}

                     =85.5

<u>Calculating Median for Math</u>

The median is the middle number in a sorted list of numbers. Since, here the number of terms is even.

So,

          Median=\frac{85+86}{2}

                         =85.5

<u>Calculating Mean for Bio</u>

As the mean of a data set is the sum of the terms divided by the total number of terms. So, from the biology mapping data as shown in attached figure

                                         \mu=\frac{83+84+85+86+87+90}{6}

                                            =\frac{515}{6}

                                            =85.83

<u>Calculating Median for Bio</u>

The median is the middle number in a sorted list of numbers. Since, here the number of terms is even.

So,

                                          Median=\frac{85+86}{2}

                                                         =85.5

Conclusion:

From the entire discussion as stated above, we determine that

  • Two measures of the middle of the data are the Median and the Mean.
  • The Median is same in both cases i.e. Median = 85.5
  • The Mean in Math case is 85.5; and in Biology case the Mean is 85.83. So, Mean is very much similar in both cases.
  • Observe in Biology case, the score 90, but it does not the represent the actual of all of her scores in biology.

The score of 90 is outliner and based on her averages, Katelyn’s scores are more or less the same.

Therefore, Katelyn is not correct because the middle of the data is about the same for each plot.

Keywords: mean, median, outliner

Learn more about mean, median, outliner from brainly.com/question/11378428

#learnwithBrainly

pantera1 [17]3 years ago
5 0

Answer:

(D)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

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The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

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r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

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-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

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