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DENIUS [597]
3 years ago
12

A coin is tossed eight times. How many different outcomes are there?

Mathematics
1 answer:
Viefleur [7K]3 years ago
5 0

The total number of different outcomes of the toss are 256.

<u>Explanation:</u>

Given:

Coin is flipped 8 times.

Number of different outcomes, n = ?

A coin is flipped eight times where each flip comes up either

heads or tails.

Considering the order of the results from each toss does matter.

Each toss has two possibilities  and the number of toss is 8.

Thus, the total outcome of the toss = 2⁸

n = 256

Therefore, total number of different outcomes of the toss are 256.

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Answer:

Option C. His answer is not correct, because the same can not be less than either attend

Step-by-step explanation:

we have

\frac{12}{15}+\frac{1}{10} =\frac{13}{25}

we know that

\frac{12}{15}=0.8

\frac{1}{10}=0.10

\frac{13}{25}=0.52

substitute

0.80+0.10=0.52 ----> is not true

therefore

His answer is not correct, because the same can not be less than either attend

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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As we know, the diagonals bisect one another in a rhombus at 90° and the angles opposite to one another are equal. This <u>proves that all four triangles constructed through the diagonals would be ≅ through SSS congruency and perpendicular to one another because the corresponding edges of the congruent triangles are also ≅</u> . Since the rhombus is divided into four equal parts, the area of one triangle into four would be equals to the area of the rhombus. Thus, <u>options 1, 3, and 4</u> are the correct answers.

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Answer:

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Step-by-step explanation:

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