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zavuch27 [327]
3 years ago
6

Simplify the expression 7+3(1-2x)

Mathematics
2 answers:
Levart [38]3 years ago
7 0

Answer:

-6x + 10

Step-by-step explanation:

7 + 3( 1 − 2x)

Distribute:

=7 + (3) (1) + (3) (−2x)

=7 + 3 + −6x

Combine Like Terms:

=7 + 3 + −6x

=(−6x) + (7 + 3)

= −6x + 10

Answer:

= −6x + 10

hope this helps and is right :)

p.s. i rlly need brainliest

tamaranim1 [39]3 years ago
3 0

Answer:

6x+10

Step-by-step explanation:

So 3*1=3

3*2x=6x

And then you add 7

3+6x+7= 6x+10

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Step-by-step explanation:

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On the track team 3/5 of the members are boys. of these boys 4/7 are 6th graders. Of the 6th grade boys on the team, 1/3 are run
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3 years ago
A company that explores for oil in the ocean is considering two new sites, A and B. The exploration will take the entire year. T
Lelu [443]

Answer:

Step-by-step explanation:

Hello!

There are two sites A and B,

Be the events A: finding oil in site Awith probability P(A)= 0.6

and B: finding oil in B with probability P(B)= 0.84

A and B are independent (there cannot be found oil of A in B and vice versa)

Remember, two events are independent when the occurrence of one of them doesn't modify the probability of occurrence of the other one in two repetitions of the experiment.

1) Find the probability that oil is found at both sites (round your answer to 2 decimal places)

If there is oil in both sites then event A and B are observed, symbolically:

P(A∩B)

Since both events are independent, the probability of the intersection of both events is equal to the product of each probability so:

P(A∩B)= P(A)*P(B)= 0.6*0.84= 0.504

2) Find the probability that oil is found at only one of the sites (round your answer to 2 decimal places)

In this case, you have two situations in which the statement can occur:

> "finding oil in A" and "not finding oil in B"

-or-

> "not finding oil in A" and "finding oil in B"

Be A' the complementary event of A, i.e. "not finding oil in region A", with probability P(A')= 1 - P(A)= 1 - 0.6= 0.4

And B' the complementary event of B, i.e. "not finding oil in region B", with probability P(B')= 1 - P(B)= 1 - 0.84= 0.16.

You can symbolize these two possible occurrences as:

Remember that "and" indicated intersection between two events, symbolized ∩, and "or" indicates the union between two events, symbolized ∪.

P((A∩B')∪(A'∩B))= P(A∩B') + P(A'∩B)= [P(A)*P(B')]+[P(A')*P(B)]= (0.6*0.16)+(0.4*0.84)= 0.432

I hope it helps!

7 0
2 years ago
What goes on the green box?
Zarrin [17]
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3 0
3 years ago
We guess, based on historical data, that 30% of graduating high-school seniors in a large city will have completed a first-year
Annette [7]

Answer:

n=\frac{0.3(1-0.3)}{(\frac{0.025}{1.96})^2}=1290.78  

And rounded up we have that n=1291

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

2) Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.3(1-0.3)}{(\frac{0.025}{1.96})^2}=1290.78  

And rounded up we have that n=1291

4 0
3 years ago
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