Answer:
h(8q²-2q) = 56q² -10q
k(2q²+3q) = 16q² +31q
Step-by-step explanation:
1. Replace x in the function definition with the function's argument, then simplify.
h(x) = 7x +4q
h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q
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2. Same as the first problem.
k(x) = 8x +7q
k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q
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Comment on the problem
In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...
h(8q² -2q) = 56q² -14q +4z
and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.
In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.
3x(y+5)
= 3xy+15x
= (Tienes que multiplicar dentro del paréntesis por 3x) <span />
Answer: 15
Step-by-step explanation: Take 12 and change the -3 to a regular 3.
(12 + 3 = 15.)
Whichever number in the question that’s bigger determines what integer it will have.
Pt 1 - how much the value goes down each year
Pt 2 - how much the car was originally worth
Answer:
The last graph with the point (2,4).
Step-by-step explanation:
Make a table of the values, then graph.
Example:
X: -2, -1, 0, 1, 2
Y: 
, 
, 
, 1, 4
