If the parent graph f(x) = x² is changed to f(x) = 2x², the vertex of the parabola will still remain (0, 0) because whenever the equation of a parabola is in the form y = ax², the vertex will always be (0, 0).
Now if <em>a</em> is a big number, the parabola will become narrower.
So it will stretch vertically and become narrower.
Answer:
Where is the triangle shown below?
Step-by-step explanation:
Answer:
Triangle APB is an isosceles triangle ⇒ 3rd answer
Step-by-step explanation:
* Lets explain the how to solve the problem
- ABCD is a square
∴ AB = BC = CD = AD
∴ m∠A = m∠∠B = m∠C = m∠D = 90°
- DPC is equilateral triangle
∴ DP = PC = DC
∴ m∠DPC = m∠PCD = m∠CDP = 60°
- In the Δs APD , BPC
∵ AD = BC ⇒ sides of the square
∵ PD = PC ⇒ sides of equilateral triangle
∵ m∠ADB = m∠BCP = 30° (90° - 60° = 30) ⇒ including angles
∴ Δs APD , BPC are congregant ⇒ SAS
- From congruent
∴ AP = BP
∴ Triangle APB is an isosceles triangle
Answer:
Jacob should pay $13.20 for the tip.
Step-by-step explanation:
The equation is: (66)(0.2) = 13.20