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Iteru [2.4K]
3 years ago
15

What is the answer to this problem

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
8 0
A possible coordinate pair could be (7, 11) or (64, 68).
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I feel like it’s C but I need gel to make sure it’s right help please I can’t really get any wrong on this
Flauer [41]
The answer is D.  It does not satisfy the second equation because 0 is not greater than 1.
4 0
3 years ago
Its -20 but how? pls helppp. ill give brainliest
MissTica

w-10=2(w+5)

w-10=2w+10

w-2w=10+10

-w=20

w=-20

4 0
2 years ago
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What is the value of x in the equation 2x - 3 = 9- 4x? o 6 o 3 O 1 02​
riadik2000 [5.3K]

Answer:

2? The last one

Step-by-step explanation:

6 0
3 years ago
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NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. In an earlier stud
SSSSS [86.1K]

Answer:

The large sample n = 190.44≅190

The  large  sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

<u>Step-by-step explanation</u>:

Given  population proportion was estimated to be 0.3

p = 0.3

Given maximum of error E = 0.04

we know that maximum error

M.E = \frac{Z_{\alpha } \sqrt{p(1-p)} }{\sqrt{n} }

The 85% confidence level z_{\alpha } = 1.44

\sqrt{n} = \frac{Z_{\alpha } \sqrt{p(1-p)} }{m.E}

\sqrt{n} = \frac{1.44X\sqrt{0.3(1-0.3} }{0.04}

now calculation , we get

√n=13.80

now squaring on both sides n = 190.44

large sample n = 190.44≅190

<u>Conclusion</u>:-

Hence The  large  sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

7 0
3 years ago
The ten students in a club are lined up in a row for a group photograph. How many different arrangements are possible if the clu
kondor19780726 [428]

We know that

if the club includes one set of identical triplets wearing matching clothes

then

the number of different arrangements that are possible is

10! / 3! = (10*9*8*7*6*5*4*3!)/3!

=604,800

The answer is

<span>604,800</span>

8 0
3 years ago
Read 2 more answers
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