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tatiyna
2 years ago
15

Use the limit definition of the derivative to find the instantaneous rate of change of

Mathematics
1 answer:
Lynna [10]2 years ago
8 0

f'(4) = 43

Explanation:

Given: f(x)=5x^2 + 3x + 3

\displaystyle f'(x)= \lim_{h \to 0} \dfrac{f(x+h) - f(x)}{h}

Note that

f(x+h) = 5(x+h)^2 + 3(x+h) + 3

\:\:\;\:\:\:\:= 5(x^2 + 2hx + h^2) + 3x + 3h +3

\:\:\;\:\:\:\:= 5x^2 + 10hx + 5h^2 + 3x + 3h +3

Substituting the above equation into the expression for f'(x), we can then write f'(x) as

\displaystyle f'(x) = \lim_{h \to 0} \dfrac{10hx + 3h + 5h^2}{h}

\displaystyle\:\:\;\:\:\:\:= \lim_{h \to 0} (10x +3 +5h)

\:\:\;\:\:\:\:= 10x + 3

Therefore,

f'(4) = 10(4) + 3 = 43

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Find two power series solutions of the given differential equation about the ordinary point x = 0. y'' + xy = 0
nalin [4]

Answer:

First we write y and its derivatives as power series:

y=∑n=0∞anxn⟹y′=∑n=1∞nanxn−1⟹y′′=∑n=2∞n(n−1)anxn−2

Next, plug into differential equation:

(x+2)y′′+xy′−y=0

(x+2)∑n=2∞n(n−1)anxn−2+x∑n=1∞nanxn−1−∑n=0∞anxn=0

x∑n=2∞n(n−1)anxn−2+2∑n=2∞n(n−1)anxn−2+x∑n=1∞nanxn−1−∑n=0∞anxn=0

Move constants inside of summations:

∑n=2∞x⋅n(n−1)anxn−2+∑n=2∞2⋅n(n−1)anxn−2+∑n=1∞x⋅nanxn−1−∑n=0∞anxn=0

∑n=2∞n(n−1)anxn−1+∑n=2∞2n(n−1)anxn−2+∑n=1∞nanxn−∑n=0∞anxn=0

Change limits so that the exponents for  x  are the same in each summation:

∑n=1∞(n+1)nan+1xn+∑n=0∞2(n+2)(n+1)an+2xn+∑n=1∞nanxn−∑n=0∞anxn=0

Pull out any terms from sums, so that each sum starts at same lower limit  (n=1)

∑n=1∞(n+1)nan+1xn+4a2+∑n=1∞2(n+2)(n+1)an+2xn+∑n=1∞nanxn−a0−∑n=1∞anxn=0

Combine all sums into a single sum:

4a2−a0+∑n=1∞(2(n+2)(n+1)an+2+(n+1)nan+1+(n−1)an)xn=0

Now we must set each coefficient, including constant term  =0 :

4a2−a0=0⟹4a2=a0

2(n+2)(n+1)an+2+(n+1)nan+1+(n−1)an=0

We would usually let  a0  and  a1  be arbitrary constants. Then all other constants can be expressed in terms of these two constants, giving us two linearly independent solutions. However, since  a0=4a2 , I’ll choose  a1  and  a2  as the two arbitrary constants. We can still express all other constants in terms of  a1  and/or  a2 .

an+2=−(n+1)nan+1+(n−1)an2(n+2)(n+1)

a3=−(2⋅1)a2+0a12(3⋅2)=−16a2=−13!a2

a4=−(3⋅2)a3+1a22(4⋅3)=0=04!a2

a5=−(4⋅3)a4+2a32(5⋅4)=15!a2

a6=−(5⋅4)a5+3a42(6⋅5)=−26!a2

We see a pattern emerging here:

an=(−1)(n+1)n−4n!a2

This can be proven by mathematical induction. In fact, this is true for all  n≥0 , except for  n=1 , since  a1  is an arbitrary constant independent of  a0  (and therefore independent of  a2 ).

Plugging back into original power series for  y , we get:

y=a0+a1x+a2x2+a3x3+a4x4+a5x5+⋯

y=4a2+a1x+a2x2−13!a2x3+04!a2x4+15!a2x5−⋯

y=a1x+a2(4+x2−13!x3+04!x4+15!x5−⋯)

Notice that the expression following constant  a2  is  =4+  a power series (starting at  n=2 ). However, if we had the appropriate  x -term, we would have a power series starting at  n=0 . Since the other independent solution is simply  y1=x,  then we can let  a1=c1−3c2,   a2=c2 , and we get:

y=(c1−3c2)x+c2(4+x2−13!x3+04!x4+15!x5−⋯)

y=c1x+c2(4−3x+x2−13!x3+04!x4+15!x5−⋯)

y=c1x+c2(−0−40!+0−31!x−2−42!x2+3−43!x3−4−44!x4+5−45!x5−⋯)

y=c1x+c2∑n=0∞(−1)n+1n−4n!xn

Learn more about constants here:

brainly.com/question/11443401

#SPJ4

6 0
1 year ago
What is the determinant of H<br><br>asap ​
dalvyx [7]

Answer:

H = 15

Step-by-step explanation:

If you need an explnation, I can provide it if needed! Cheers!

3 0
3 years ago
On Venus how can you overcome extreme temperature and microgravity
matrenka [14]
Mercury is very different than Earth.  I think Mercury is a very hot planet, and because of the gravity and other conditions - look these up online - Humans and other life on Earth cannot live on Mercury, much less visit without being fully protected.  Temperature on Mercury 426 degrees Celsius, about 800 degrees fahrenheit - very hot.  You would want your space craft to completely protected from these temperatures, think of some materials you could use, and how thick you would need them?  What material protects from heat?   As far as vacuum conditions, and gravity, you will need to have that included as well.Maybe you would just wear a type of clothing to protect against bumping around in your space craft since you will not have gravity, you will also want to think about food!  
8 0
3 years ago
You have one type of nut that sells for $4.50/lb and another type of nut that sells for $8.00/lb. You would like to have 28 lbs
-Dominant- [34]

Answer:

I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.

Step-by-step explanation:

Since I have one type of nut that sells for $ 4.50 / lb and another type of nut that sells for $ 8.00 / lb, and I would like to have 28 lbs of a nut mixture that sells for $ 7.80 / lb, to determine how much of each nut will I need to obtain the desired mixture, the following calculation must be performed:

8 x 0.95 + 4.5 x 0.05 = 7.825

8 x 0.94 + 4.5 x 0.06 = 7.79

0.94 x 28 = 26.32

26.4 x 8 + 1.6 x 4.5 = 218.4

218.4 / 28 = 7.8

Thus, I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.

7 0
3 years ago
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