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Dmitrij [34]
3 years ago
9

A _____ is a point that helps to define an ellipse. ...?

Mathematics
2 answers:
Paha777 [63]3 years ago
8 0
I would say focus. I hope this helps.
mezya [45]3 years ago
3 0
Foci.
An ellipse is defined by two focal points.
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Evaluate the function below for x = 2.<br>f (x) = 4x^3 - x^2 - 5x+7<br>​
nexus9112 [7]

Answer: f(2)=25

Step-by-step explanation:

You know that the given function is:

f(x)=4x^3-x^2-5x+7

You know that you must evaluate this function for x=2.

Then, to evaluate the function for x=2, you need to substitute this value into the given function and simplify it.

Therefore, you get:

f(x)=4x^3-x^2-5x+7\\f(2)=4(2)^3-(2)^2-5(2)+7\\f(2)=4(8)-(4)-10+7\\f(2)=32-4-10+7\\f(2)=25

So, the answer is: f(2)=25

8 0
3 years ago
Please help me with this problem i have been struggling!
adoni [48]

Answer:

14

First multiply

1 and 3/4 by 8 and then you got your answer

5 0
3 years ago
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Draw a graph of y equals 7 + 4 x - 2x squared
gtnhenbr [62]

Answer:

thanks man i really needed points

Step-by-step explanation:

6 0
3 years ago
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WHO KNOWS THE ANSWER TO THESE
aliya0001 [1]
I don’t know all of them but the ones across 8 are the same as 8 so 1,4, and 6 are all 42° :)
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The first step for deriving the quadratic formula from the quadratic equation, 0 = ax2 bx c, is shown.step 1: –c = ax2 bxwhich b
Ksju [112]

Answer:

option (b) is correct.

First step to solve for deriving the quadratic formula from the quadratic equation is completing the square.

Step-by-step explanation:

Given : the quadratic equation ax^2+bx+c=0

We have to find the first step for deriving the quadratic formula from the quadratic equation.

Quadratic formula  is given by \frac{-b\pm\sqrt{b^2-4ac}}{2a}

Consider the given quadratic equation ax^2+bx+c=0

Divide the equation by a, we get,

x^2+\frac{b}{a}x+\frac{c}{a}=0

Take \frac{c}{a} to other side, we get,

x^2+\frac{b}{a}x=-\frac{c}{a}

Add (\frac{b}{2a})^2 to both side, we get,

x^2+\frac{b}{a}x+(\frac{b}{2a})^2=(\frac{b}{2a})^2-\frac{c}{a}

Thus, the left side is in the form of (a+b)^2=a^2+b^2+2ab

On solving, we get,

(x+\frac{b}{2a})^2=(\frac{b}{2a})^2-\frac{c}{a}

Then solve for x , we get quadratic formula \frac{-b\pm\sqrt{b^2-4ac}}{2a}

Thus, first step to solve for deriving the quadratic formula from the quadratic equation is completing the square.

Thus, option (b) is correct.

3 0
3 years ago
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