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3 years ago

Tina runs at a reate of 8 miles per hour. at that rate, how many miles will she run in 12 minutes

Mathematics

2 answers:

STALIN [3.7K]3 years ago

4 0

The correct answer would be 1.6 miles in 12 minutes, hope this helps!

Paul [167]3 years ago

3 0

I think that she would run about 12 minutes

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Which answers describe the shape below? Check all that apply.

serg [7]

Answer:

Trapezoid and Quadrilateral

Step-by-step explanation:

Trapezoid because it has four sides that are not equal You may not be familiar with this figure because most trapezoids don't look like this. It is a quadrilateral because it is a figure that has 4 sides.

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2 years ago

it takes 47 minutes for 7 people to paint 7 walls. how many minutes does it take 20 people to paint 20 walls?

4vir4ik [10]

Answer:

7 people, 7 walls, 48 minutes

Each person paints 1 wall in 48 minutes

20 persons, 20 walls

Each person can paint 1 wall in 48 minutes so it will take 48 minutes.

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3 years ago

If sin theta = - squrt.3/2 and pi < theta < 3pi/2, what are the values of cos theta and tan theta?

Kryger [21]

So this first wants you to find where sin is √3/2 when θ is between π and 3π/2. θ would therefore be located at 2π/3.

Now plug in the value of θ for cosine:

cos (2π/3) = -1/2

And tangent:

tan (2π/3) = -√3/3

7 0

3 years ago

Read 2 more answers

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

4 0

2 years ago

What is the value of x in the equation 8x – 2y = 48, when y = 4? 6 7 14 48

natita [175]

Answer:

x=7

Step-by-step explanation:

7 0

3 years ago