All categories

3 years ago

Which of the following is the equation of a line that is parallel to y=5x-3 and that passes through the point (2,5)

Mathematics

1 answer:

Travka [436]3 years ago

3 0

parallel to the line y = 5x - 3, so the other lines must have same slope m = 5

y - y1 = m(x - x1)

y - 5 = 5(x-2)

y = 5x - 10 + 5

y = 5x - 5

You might be interested in

Tom found that a linear equation with one variable (the variable x) can be transformed into an equivalent equation that has no s

vesna_86 [32]

Answer:

0=1

Step-by-step explanation:

0=1 is not equal

5 0

3 years ago

Read 2 more answers

A cube has a surface area of 96 square inches. What is the volume of the cube

denpristay [2]

The formula for the surface area of a cube is: SA= 6((length of side)^2).
So if the surface area is 96, first divide by 6. And you get 16. Next you find the square-root of 16 and get 4. So the length of each side is 4 inches.
The formula for volume of a cube is V=(length of side)^3.
So 4 raised to the third power is: 4*4*4.
The volume of the cube is 64 inches cubed.

4 0

3 years ago

If you sleep 8 hours out of 24 hours, what percent of the time do you sleep?

olasank [31]

Answer:

It is 8/24 = 1/3 (~33.33%)

7 0

3 years ago

Read 2 more answers

Dan recently bought a new mountain bike for $550. His friend works

Wittaler [7]

$990
550 x .80 = 440
$550 + $440 = $990

8 0

3 years ago

Find the Laplace transformation of each of the following functions. In each case, specify the values of s for which the integral

MAVERICK [17]

Answer:

a. $\frac {2} {s-1}$ converges to s> 1.

b. $\frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $- \frac {2}{s + 3}$ converges to s> - 3.

d. $\frac {s}{s^2 + 25}$ converges to s> 0.

e. $\frac {10} {s^2 + 1}$ converges even s> 0.

f. $\frac {12}{s^2 + 4}$ converges to s> 0.

g. $-\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $\frac {1} {s ^ 2 + 4}$ converges to s> 0.

Step-by-step explanation:

a. $L \left\{2e^t \right\} = 2L \left\{e^t \right\} = 2 \cdot \frac {1} {s-1} = \frac {2} {s-1}$ converges to s> 1.

b. $L \left\{3e^{5t-3} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = \frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3}$ converges to s> - 3.

d. $L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25}$ converges to s> 0.

e. $L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1}$ converges even s> 0.

f. $L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4}$ converges to s> 0.

g. $L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $L\left\{\sin \left(t\right)\cos \left(t\right)\right\} = L\left\{\sin\left(2t\right)\frac{1}{2}\right\} =\frac{1}{2}\cdot \frac{2}{s^2+4} = \frac {1} {s ^ 2 + 4}$ converges to s> 0.

7 0

3 years ago