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castortr0y [4]
2 years ago
15

Heeeeeeeeeeeeeeeellllppp

Mathematics
1 answer:
Genrish500 [490]2 years ago
4 0

Answer:

The Area = 28.26 or 28.27 depends if you round or not

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How do you graph this on graph paper using these coordinates? The graph is in shape of a cross. (9,4) (6,-12) (9,-12) (10,-8) (1
TiliK225 [7]
Remember:
(x, y)
      (y-axis)
         |
         |
--------|-------- (x-axis)
          |
          |

You just have to...
fiddle...
around with the graph.
And try to figure out things.

I spent 20 minutes on this.
and couldn't get quite close to a cross.
sorry.

4 0
3 years ago
What is the volume of this cone
wel

Answer:

6ix9ines a snitch

Step-by-step explanation:

aka rat

6 0
3 years ago
PLEASE HELP ME
madam [21]

Answer:

thursday, Tuesday, monday, Wednesday

3 0
2 years ago
F(x)=-x^2-5 find the range
lina2011 [118]

x =  \frac{ - b}{2a}  \\  =   \frac{0}{2(1)}  = 0 \\ f(0) = (0)^{2}  - 5 \\  = 0 - 5 =  - 5
The vertex is at (0,-5), therefore the range goes from (-infinity, - 5]
4 0
3 years ago
In a version of the game of roulette, a steel ball is rolled onto a wheel that contains 19 red, 19 black and 2 green slots. If t
trasher [3.6K]

Answer:

The probability is 0.3576

Step-by-step explanation:

The probability for the ball to fall into the green ball in one roll is 2/1919+2 = 2/40 = 1/20. The probability for the ball to roll into other color is, therefore, 19/20.

For 25 rolls, the probability for the ball to never fall into the green color is obteined by powering 19/20 25 times, hence it is 19/20^25 = 0.2773

To obtain the probability of the ball to fall once into the green color, we need to multiply 1/20 by 19/20 powered 24 times, and then multiply by 25 (this corresponds on the total possible positions for the green roll). The result is 1/20* (19/20)^24 *25 = 0.3649

The exercise is asking us the probability for the ball to fall into the green color at least twice. We can calculate it by substracting from 1 the probability of the complementary event: the event in which the ball falls only once or 0 times. That probability is obtained from summing the disjoint events: the probability for the ball falling once and the probability of the ball never falling. We alredy computed those probabilities.

As a result. The probability that the ball falls into the green slot at least twice is 1- 0.2773-0.3629 = 0.3576

5 0
3 years ago
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