Answer:
-9m-4
Step-by-step explanation:
Move the -4 to the right hand side by adding 4 to both sides, like this: To the left hand side:
-4 + 4 = 0
9m ‹ 5m
Start by finding the slope of the line by doing m(slope)=y2-y1 over x2-x1 using the pairs and then plug in the y and x of one of the points into the equation y=mx+b (y in the y and x in the x spot) and solve for b. Then plug the slope (can be a fraction shouldn’t be decimal) and y-intercept (b) back in the equation of a line above and you have your answer!
Answer:
<u>3.75 cm^2</u>
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Step-by-step explanation:
Area of a rectangle = Length x Width.
If we are given that the length is 5 cm and width is 3/4 cm ( you could convert this to a 0.75 if you want to as well ) we can plug this in:
Area = 5 cm x 3/4 cm
Solving for Area we get:
Area = 3.75 cm^2.
Given that both triangles are similar and have a scale of 5:2, therefore the true statement about the proportions of the sides is:
B. AC/DF = 5/2
<h3>What are Similar Triangles?</h3>
- Similar triangles have corresponding side lengths that are proportional in length.
- Similar triangles have same shape but are of different sizes.
Thus, given that both triangles are similar and have a scale of 5:2, therefore the true statement about the proportions of the sides is:
B. AC/DF = 5/2
Learn more about similar triangles on:
brainly.com/question/2644832
<u>We are given:</u>
The function: y = -16t² + 64
where y is the height from ground, t seconds after falling
<u>Part A:</u>
when the droplet would hit the ground, it's height from the ground will be 0
replacing that in the given function:
0 = -16t² + 64
16t² = 64 [adding 16t² on both sides]
t² = 4 [dividing both sides by 16]
t = 2 seconds [taking square root of both sides]
<u>Part B:</u>
for second droplet,
height from ground = 16 feet
time taken = t seconds
acceleration due to gravity = 10 m/s²
initial velocity = 0 m/s
h = ut + (1/2)at² [second equation of motion]
16 = (0)(t) + (1/2)(10)(t²)
16 = 5t²
t² = 16/5
t = 1.8 seconds (approx)
Therefore, the second droplet takes the least amount time to hit the ground
