Let present age of women be x.
Then,Present age of her daughter be y.
According to the question,
<u>Two years ago,</u>
Woman age = x - 2
Her daughter age = y - 2
Woman was 7 times old as her daughter. [ Given ]
x - 2 = 7 ( y - 2 )
=> x - 2 = 7y - 14
=> x - 2 + 14 = 7y
=> x + 12 = 7y ....( i )
<u>A</u><u>f</u><u>t</u><u>e</u><u>r</u><u> </u><u>Three years </u>,
Woman age = x + 3
Her daughter age = y + 3
she would be 4 times old as the girl. [ Given ]
x + 3 = 4 ( y + 3 )
=> x + 3 = 4y + 12
=> x = 4y + 12 - 3
=> x = 4y + 9....( ii (
Now,
★ Putting the value of x = 4y + 9 from equation ( ii ) in equation ( i ),we get
x + 12 = 7y
=> 4y + 9 + 12 = 7y
=> 21 = 7y - 4y
=> 21 = 3y
=> 3y = 21
=> y = 21/3
=> y = 7
And,
x = 4y + 9
★ Putting the value of y in equation ( ii ), we get
x = 4 × 7 + 9
x = 28 + 9
x = 37
Hence, the present age of women is 37 years and her daughter age is 7.
Answer:
(- 1, 2 )
Step-by-step explanation:
2x + 5y = 8 → (1)
x - 2y = - 5 → (2)
multiplying (2) by - 2 and adding to (1) will eliminate x
- 2x + 4y = 10 → (3)
add (1) and (3) term by term to eliminate x
0 + 9y = 18
9y = 18 ( divide both sides by 9 )
y = 2
substitute y = 2 into either of the 2 equations and solve for x
substituting into (1)
2x + 5(2) = 8
2x + 10 = 8 ( subtract 10 from both sides )
2x = - 2 ( divide both sides by 2 )
x = - 1
solution is (- 1, 2 )
Answer:
Please see attachment
Step-by-step explanation:
Please see attachment
Answer:
it's a perfect cube only....
Only a guess but 69.5 7
9
