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expeople1 [14]
3 years ago
10

Some of the steps in the derivation of the quadratic formula are shown. Step 3: –c + StartFraction b squared Over 4 a EndFractio

n = a(x squared + StartFraction b Over a EndFraction x + StartFraction b squared Over 4 a squared EndFraction) Step 4a: –c + StartFraction b squared Over 4 a EndFraction = a(x + StartFraction b Over 2 a EndFraction) squared Step 4b: negative StartFraction 4 a c Over 4 a EndFraction + StartFraction b squared Over 4 a EndFraction = a(x + StartFraction b Over 2 a EndFraction) squared Which best explains or justifies Step 4b? factoring a polynomial multiplication property of equality converting to a common denominator addition property of equality
Mathematics
2 answers:
icang [17]3 years ago
8 0

Answer:

The square root of terms separated by addition and subtraction cannot be calculated individually.

Step-by-step explanation:

svlad2 [7]3 years ago
5 0

Answer:

The square root of terms separated by addition and subtraction cannot be calculated individually

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59 points!!!!!!!
MariettaO [177]
A=a+b
2h use this method when you do? - 14a + 200b + 16h = 1712
8 0
3 years ago
Read 2 more answers
What is the value of x enter your answer in the Box
lina2011 [118]
The x is 176.54 cm.
i use pythagorean thearem
{c}^{2}  =  {a}^{2}  +  {b}^{2}

4 0
3 years ago
Read 2 more answers
BRAINLIEST GIVEN TO BEST ANSWER
lbvjy [14]

Answer:

Slope = \frac{1}{4}

Step-by-step explanation:

Slope of a straight line passing two points (x_1,y_1) and (x_2,y_2) is given by the formula,

m = \frac{y_2-y_1}{x_2-x_1}

From the graph attached,

Line is passing through two points (20, 5) and (80, 20),

Therefore, slope of the line will be,

m = \frac{20-5}{80-20}

m = \frac{1}{4}

The slope is \frac{1}{4}.

3 0
3 years ago
1 /3 + 1 /9 / (7/10 * 5 / 4 )
Ludmilka [50]

Answer:

0.46

Hope it helps..

have a great day : )

7 0
3 years ago
When an electric current passes through two resistors with resistance r1 and r2, connected in parallel, the combined resistance,
kondaur [170]

Answer:

a)

The combined resistance of a circuit consisting of two resistors in parallel is given by:

\frac{1}{R}=\frac{1}{r_1}+\frac{1}{r_2}

where

R is the combined resistance

r_1, r_2 are the two resistors

We can re-write the expression as follows:

\frac{1}{R}=\frac{r_1+r_2}{r_1r_2}

Or

R=\frac{r_1 r_2}{r_1+r_2}

In order to see if the function is increasing in r1, we calculate the derivative with respect to r1: if the derivative if > 0, then the function is increasing.

The derivative of R with respect to r1 is:

\frac{dR}{dr_1}=\frac{r_2(r_1+r_2)-1(r_1r_2)}{(r_1+r_2)^2}=\frac{r_2^2}{(r_1+r_2)^2}

We notice that the derivative is a fraction of two squared terms: therefore, both factors are positive, so the derivative is always positive, and this means that R is an increasing function of r1.

b)

To solve this part, we use again the expression for R written in part a:

R=\frac{r_1 r_2}{r_1+r_2}

We start by noticing that there is a limit on the allowed values for r1: in fact, r1 must be strictly positive,

r_1>0

So the interval of allowed values for r1 is

0

From part a), we also said that the function is increasing versus r1 over the whole domain. This means that if we consider a certain interval

a ≤ r1 ≤ b

The maximum of the function (R) will occur at the maximum value of r1 in this interval: so, at

r_1=b

6 0
3 years ago
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