Set up an system:
x+y=52
x=y-2
Substitute in:
(y-2)+y=52
2y-2=52
2y=54
y=27
27-2=25
The answers are 27 and 25
Answer:
what do you need?
Step-by-step explanation:
Answer: nickels = 13, dimes = 7, quarters = 14
<u>Step-by-step explanation:</u>
First, set up the equations for each coin:

Next, the sum of the coins is $4.85 so substitute and solve for the variable:
Nickels + Dimes + Quarters = Sum
(0.30 + 0.05d) + 0.10d + 0.50d = 4.85
0.30 + 0.65d = 4.85
0.65d = 4.55
d = 7
Lastly, plug the d-value into the quantity equation for the nickels and quarters to find their quantity.
nickels: 6 + d = 6 + (7) = 13
quarters: 2d = 2(7) = 14
Set up the equation by writing the number of students in the ratio as a fraction:
3/4= (245-x)/x Cross multiply:
3x= 4(245-x) Multiply on right:
3x= 980-4x Add 4x on both sides:
7x= 980 Divide both sides by 7:
x= 140 this is how many girls there are. And:
245-140= 105= boys
Yes I think I’m gonna go go to go home with homework homework done today I will be there in green bath