Answer:
135° and 225°
Step-by-step explanation:
basically you want to find the value of x between 0 and 360 in this equation
cos x/2 = -(√2)/2
assume x/2 as n, so
cos n = -(√2)/2
n = 45°
then remember the quadrant system
0-90 1st quadrant, all is POSITIVE
90-180 2nd quadrant, only SIN has positive value
180 - 270 3rd quadrant, only TAN has positive value
270 -360 4th quadrant, only COS positive here.
so if you try to find negative value look into 2nd and 3rd quadrant that related 45° to x-axis (0°or 180°)
so the value of x is
180 - 45 = 135° (2nd quadrant) and
180 + 45° = 225° (3rd quadrant)
Answer:
Less then
Step-by-step explanation:
therietic prob is 8
Answer:
There are no domains so 0
Step-by-step explanation:
The domain of any function is simply all the possible numbers you can input for x
without violating the rules of math.
we cannot have a negative number for x (its against the laws of math), so the domain would be all non-negative numbers
:) Hoped this helped
Answer:
.3750
Step-by-step explanation:
sorry if this is wrong. I don't understand
Answer:
Step-by-step explanation:
The breaking point for the graph (if there was one), is one. That means at one the function you use changes.
It goes from x^2 to 2x + 1
Answer A
Here's the catch. Where is 0? Zero is less than one. So what do you use? The answer is that f(x) = x^2
Answer B
if f(x) = x^2 then wherever you see an x, you put in 0.
f(x) = x^2
f(0) = 0^2
You could multiply 0 by itself a million times and it would still get 0.
f(0) = 0
