Solution:
To classify the system of equations as no solutions, the lines must be parallel (Not intersect).
<u>First, let's identify the equation forming the line.</u>
- Slope = Rise/Run = 2/-3 = -0.66
- Y-intercept = 0
- Equation formed: y = -2/3
We also know that the slope of the equation must be -1.5.
<u>A) 2x + 3y = 0</u>
- 3y = 0 - 2x
- => 3y = -2x
- => (y = -2x/3) ∦ (y = -2x/3)
<u>B) 2x + 3y = 6</u>
- => 3y = -2x + 6
- => (y = -2x/3 + 2) ║ (y = -2x/3)
<u>C) 2x - 3y = 9</u>
- => -3y = -2x + 9
- => y = -2x/-3 + 9/-3
- => (y = 2x/3 - 3) ∦ (y = -2x/3)
<u>D) y = 3x + 2</u>
- (y = 3x + 2) ∦ (y = -2x/3)
Option B is correct.
I just met a friend for the first year old man who
Single solution.
They have different slopes and must therefore have 1 solution.
Answer: it wpuld be 12 because 2 times 6 equals 12 and 3 times 6 is 18
Step-by-step explanation:
