3 years ago

Tickets to a play cost $5 at the door and $4 in advance. The theater club wants to raise $400 from the play.

1 answer:

4 0

The theatre needs to sell 100 tickets in advance. or 80 tickets at the door to reach $400.
They would need to sell 48 tickets at the door to reach their goal.

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On Monday, I bought 1 dog and 3 cats for a total cost of $7.75. On Tuesday, 1

Zina [86]

Answer: The cats cost more

also there is a typo

Step-by-step explanation:

I bought 1 dog and 3 cats a total cost of $7.75. the three cats cost more so in all the cats must cost 3.56$

4 0

3 years ago

Pls can someone help me<br><img src="https://tex.z-dn.net/?f=%20log10%20%5Csqrt%7B36%7D%20%20%2B%20%20%20%20log10%20%20%5Csqrt%7

Firlakuza [10]

Answer:

$= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

Step-by-step explanation:

Given the expression $log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\$

According to the law of logarithm;

loga + log b = log(ab) and log a - log b = log(a/b)

The given expression becomes;

$log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\= log_{10}(\frac{\sqrt{36} \times \sqrt{2} }{\sqrt{7} })\\= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$