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inn [45]
3 years ago
9

Tickets to a play cost $5 at the door and $4 in advance. The theater club wants to raise $400 from the play.

Mathematics
1 answer:
natima [27]3 years ago
4 0
The theatre needs to sell 100 tickets in advance. or 80 tickets at the door to reach $400.  
They would need to sell 48 tickets at the door to reach their goal.


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Josh pays $19.60 for a pack of 4 towels find the unit price in dollars per towel. If necessary, round your answer to the nearest
Elena-2011 [213]

Answer: $4.9 each towel

Step-by-step explanation:

You divide 19.6 by 4

5 0
3 years ago
What is the answer to > solve 4cos (theta/3) -2 = 0, over [0, 4pi)
Vesna [10]

Hello from MrBillDoesMath!

Answer:  

@ =   pi/3 (or 60 degrees) or @ = 7 pi/3 (or 420 degrees)


Discussion:

Let "@' denote the angle "theta". We are asked to find @ in the interval [0, 4 pi)

where

4cos(@) - 2 = 0.                Adding 2 to both sides

4 cos(@) - 2 +2 = 2  =>

4 cos(@) = 2                     Divide both sides by 4

cos(@) = 2/4 = 0.5


This implies that @ =   pi/3 (or 60 degrees) or @ = (pi/3 + 2pi) = 7 pi/3 (or 420 degrees)


Thank you,

MrB

5 0
3 years ago
How do you solve this equation . Q=3a+5ac
mr_godi [17]
A "solution" would be a set of three numbers ... for Q, a, and c ... that
would make the equation a true statement.

If you only have one equation, then there are an infinite number of triplets
that could do it.  For example, with the single equation in this question,
(Q, a, c) could be (13, 1, 2) and they could also be  (16, 2, 1).
There are infinite possibilities with one equation.

In order to have a unique solution ... three definite numbers for Q, a, and c ...
you would need three equations.
8 0
3 years ago
The independent variable is the variable that:
LuckyWell [14K]
A. Is changed or manipulated in the experiment
3 0
3 years ago
Jackson is starting an exercise program. The first day he will spend 30 minutes on the treadmill. He will increase his time on t
yulyashka [42]

Answer:

40 minutes.

Step-by-step explanation:

  • time spent on the thread mill as a function of d(day) = t(d)

= 30 +2(d-1) minutes

[where d represents day number]

(when d is 1 the time spent should be 30

so substitute d=1 and check it will be 30 only.

on first day he will spend 30 minutes so, I added 30 .

and on every additional day( these additional days are excluding first day), he will increase the time by 2 minutes.so, I added 2(d-1) to initial 30 minutes)

  • so, T(6), the minutes he will spend on the treadmill on day 6=

=30+2(6-1)

=30+2(5)

=30+10

=40 minutes

3 0
3 years ago
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