Answer:
∠BDC=50°
Step-by-step explanation:
∠BDC=∠A[angles at the same segment)
∠A= 180-(65+65)=180-130= 50°
so, ∠BDC=50°
<em>MARK ME BRAINLIEST</em>
Answer:
2/9
Step-by-step explanation:
We have 3 video games
I will assume that pirates have a water theme, so 2 have a water theme
That leaves 1 game with no water theme
P (no water theme) = games with no water theme/ total
=1/3
The games are 6 7 and 9 dollars
2 games are at least 7 dollars
P( at least 7 dollars) = games at least 7/ total
=2/3
P ( no water theme at least 7 dollars) = P (no water theme) * P( at least 7 dollars)
= 1/3*2/3
= 2/9
Answer:
Given the expression: 
Let the value of the given expression in radians be 
then;

......[1]
We know the value of 
Substitute the given value in [1] we have;

Since, the value of
is 0, therefore, the value of
is in the form of:
; where n is the integer.
At n =0, 1 and 2, {Since, n is the integer}
Value of
and
therefore, the answer in radians either
or
I think you can put bench mark place valie round tenth thousnadth