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3 years ago

What is 5.7% expressed as a decimal?

Mathematics

2 answers:

strojnjashka [21]3 years ago

8 0

Move the decimal left twice. 0.057

nordsb [41]3 years ago

8 0

I think the answer is 0.057

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A group of 100 students took a quiz. Their average score was 76 points. If the average score for the boys was 80 points and the

sveta [45]

Answer:

The number of girls participated in quiz is 40 .

Step-by-step explanation:

Given as :

Total number of students took quiz = 100

Average score of 100 students = 76 points

The Average score of boys = 80 points

The Average score of girls = 70 points

Let The number of boys participated in quiz = b

Let The number of girls participate in quiz = g

Now, According to question'

Total number of students took quiz = number of boys participated in quiz + number of girls participated in quiz

Or, b + g = 100 ........A

<u>Again</u>

∵ Average score of 100 students = 76 points

∴ Total score of 100 students = 76 × 100 = 7600

So, Average score of boys × number of boys participated + Average score of girls × number of girls participated = Total score of 100 students

Or, b × 80 + g × 70 = 7600

Or, 80 b + 70 g = 7600 .........B

Now, Solving equation A and B

(80 b + 70 g ) - 70 ×( b + g ) = 7600 - 70 × 100

I.e (80 b - 70 b) + (70 g - 70 g) = 7600 - 7000

Or, 10 b + 0 = 600

∴ b = $\dfrac{600}{10}$

i.e b = 60

So, The number of boys participated in quiz = b = 60

Put the value of b into eq A

∵ b + g = 100

So, g = 100 - b

Or, g = 100 - 60

i.e g = 40

So, The number of girls participated in quiz = g = 40

Hence, The number of girls participated in quiz is 40 . Answer

6 0

3 years ago

What is the area of the sector ?

worty [1.4K]

They forget to say "not to scale". I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first. By the Law of Cosines

$x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ$

We have an isosceles triangle formed by two radii of 9 cm and x=PQ. By the Law of Cosines again,

$x^2 = 9^2 + 9^2 - 2(9)(9) \cos B$

$x^2 = 162 - 162 \cos B$

$\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}$

$\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}$

$B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)$

The area of the circle is the fraction given by the angle,

$A = \dfrac{B}{360^\circ} \pi r ^2$

$A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2$

$A\approx 24.7474332960707$

Answer: 24.7 sq cm

8 0

3 years ago

Can the sine rule relationship in trigonometry be used with non right angled triangle

Reika [66]

Answer:

Below

Step-by-step explanation:

You can use it if you added a hight.

When you a hight you are creating a right triangle. If not you cannot use directly

7 0

4 years ago

Read 2 more answers

Please help and also how did u get ur answer

s344n2d4d5 [400]

9514 1404 393

Answer:

$364,130.83

Step-by-step explanation:

You put in $160 monthly for 32 years, so your contribution is ...

$160×12×32 = $61,440

The difference between the account balance and your contribution is ...

$425,570.83 -$61,440 = $364,130.83

There is $364,130.83 more in the account than what you put in.

8 0

3 years ago

If I'm 4years and my brother is half of my age now I'm 44 how old is he ?

Gemiola [76]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers