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babunello [35]
3 years ago
15

Suppose the area of a circle is 4π. What is its diameter?

Mathematics
2 answers:
mart [117]3 years ago
6 0
Area=pi times radius^2 so

if area=4pi=pi times r^2
4 times pi=r^2 times pi
divide both sdies by pi
4=r^2
square root
2=radius since legnth cannot be negative

radius=1/2 diamters
2 radius=diameter
2(2)=diameter=4
diameter=4
Ganezh [65]3 years ago
6 0
A=4\pi=\pi r^2\\
4\pi=\pi r^2\\
r^2=4\\
r=2\\\\
d=2r\\
d=2\cdot2\\
d=4
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f(-3) = 51

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3 years ago
5. Mis the midpoint of CD. C has coordinates (-1,-1) and
lana66690 [7]

Answer/Step-by-step Explanation:

4. Midpoint (M) of AB, for A(-2, -3) and B(1, 2) is given as:

M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})

Let A(-2, -3) = (x_1, y_1)

B(1, 2) = (x_2, y_2)

Thus:

M(\frac{-2 + 1}{2}, \frac{-3 + 2}{2})

M(\frac{-1}{2}, \frac{-1}{2})

5. Given M(3, 5) as midpoint of CD, and C(-1, -1),

let C(-1, -1) = (x_2, y_2)

D(?, ?) = (x_1, y_1)

M(3, 5) = (\frac{x_1 +(-1)}{2}, \frac{y_1 +(-1)}{2})

Rewrite the equation to find the coordinates of D

3 = \frac{x_1 - 1}{2} and 5 = \frac{y_1 - 1}{2}

Solve for each:

3 = \frac{x_1 - 1}{2}

3*2 = \frac{x_1 - 1}{2}*2

6 = x_1 - 1

6 + 1= x_1 - 1 + 1

7 = x_1

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5 = \frac{y_1 - 1}{2}

5*2 = \frac{y_1 - 1}{2}*2

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10 + 1= y_1 - 1 + 1

11 = y_1

y_1 = 11

Coordinates of D is (7, 11)

7 0
3 years ago
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