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Alexeev081 [22]
3 years ago
13

A leaky pool loses 2 1/4 inches of water each day. Jermaine and Mildred are asked to determine the change in the amount of water

in the pool over 5 days.
Jermaine’s Solution Mildred’s Solution

5(-2 1/4) 5(-2 1/4)
5(-2 -1/4) 5(-2 -1/4)
-10 -1/4 -10 -5/4
-10 1/4 -11 1/4

Which describes the reasoning used to determine whose solution is correct?

A. Jermaine is correct because -10 -1/4 equals -10 1/4.
B.Jermaine is correct because he distributed 5 correctly.
C.Mildred is correct because she multiplied 5 by –2 but not by -1/4.
D.Mildred is correct because she distributed 5 correctly.
Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0

Answer: D. Mildred is correct because she distributed 5 correctly.

Step-by-step explanation:

Since, the loss of water in one day = 2\frac{1}{4}\text{ inches}

⇒ The loss of water in 5 days = 5(2\frac{1}{4})\text{ inches}

⇒ The loss can be written with negative sign,

Thus, the expression that shows the changes in quantity of water in 5 days,

-5(2\frac{1}{4})

=-5(2+\frac{1}{4})

=5(-2-\frac{1}{4})

=-10-\frac{5}{4}

=-10-1\frac{1}{4}

=-10-1-\frac{1}{4}

=-11-\frac{1}{4}

=-11\frac{1}{4}

Since, the above steps are similar to that of Mildred's solution,

⇒ Mildred is correct.

Also, By the above explanation it is clear that jermaine incorrectly distribute 5 in his third steps.

⇒ Option D is correct.

DochEvi [55]3 years ago
5 0
Mildred's solution is correct.

5(-2 1/4) = 5(-2 + -1/4) = 5(-2) + 5(-1/4) = -10 + -5/4 = -10 + -1 1/4 = -11 1/4
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Solve for C when 9=c(c-8)<br><br> Can you show your work too? This question confuses me!
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Step-by-step explanation:

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A street light is mounted at the top of a 15-ft-tall pole. A man 6 feet tall walks away from the pole with a speed of 5 ft/s alo
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Answer:

25/3 ft/s

Step-by-step explanation:

Height of pole , h=15 ft

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DE=BE-BD=y-x

All right triangles are similar

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Therefore,

\frac{AB}{CD}=\frac{BE}{DE}

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5y-5x=2y

5y-2y=5x

3y=5x

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Differentiate w.r.t t

\frac{dy}{dt}=\frac{5}{3}\frac{dx}{dt}

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