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Rama09 [41]
2 years ago
9

Part C

Mathematics
1 answer:
ehidna [41]2 years ago
4 0

Answer:

Dec 7, 2020 — Calculate the ratio of the lengths of the two line segments formed on each transversal. You will have two sets of calculations. Round your ... sets of calculations. Round your answers to the hundredths place. What do you notice about the ratios of the lengths for each transversal? How do they compare? 1.

Step-by-step explanation:

brainlist please or else ill kill you understand

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$6,400

Step-by-step explanation:

9100-1100

8000

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8000-1600

$6,400

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4.8a - 6.3b - 2.1a + 7b
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First, you combine like terms. I would start by circling the term and the sign in front of it. (A term is a piece separated by an addition/subtraction sign.) You can only combine terms with the same variable. 4.8a-2.1a-6.3b+7b is the same as your equation, just rearranged. Then, subtract (4.8a-2.1a) which is 2.7a. Add (-6.3b to 7b) The answer is 0.7b. If you have any questions, you can message me!
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Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC
e-lub [12.9K]

Answer:

DC=\frac{8}{3}\ units

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

so

<em>In the right triangle ABM</em>

Applying the Pythagorean Theorem

BM^2=AB^2-AM^2

we have

AB=5\ units\\AM=x\ units

substitute

BM^2=5^2-x^2

BM^2=25-x^2 -----> equation A

<em>In the right triangle BMC</em>

Applying the Pythagorean Theorem

BM^2=BC^2-MC^2

we have

BC=7\ units\\MC=AC-AM=(9-x)\ units

substitute

BM^2=7^2-(9-x)^2

BM^2=49-(81-18x+x^2)  

BM^2=49-81+18x-x^2

BM^2=-x^2+18x-32 ----> equation B

equate equation A and equation B

-x^2+18x-32=25-x^2

solve for x

18x=25+32\\18x=57\\\\x=\frac{57}{18}

Simplify

x=\frac{19}{6}

<em>Find the length of DC</em>

DC=AC-2x

substitute the given values

DC=9-2(\frac{19}{6})

DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units

8 0
3 years ago
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