The period of a simple pendulum is given by:
![T=2 \pi \sqrt{ \frac{L}{g} }](https://tex.z-dn.net/?f=T%3D2%20%5Cpi%20%20%5Csqrt%7B%20%5Cfrac%7BL%7D%7Bg%7D%20%7D%20)
where L is the pendulum length, and g is the gravitational acceleration of the planet. Re-arranging the formula, we get:
![g= \frac{4 \pi^2}{T^2}L](https://tex.z-dn.net/?f=g%3D%20%5Cfrac%7B4%20%5Cpi%5E2%7D%7BT%5E2%7DL%20)
(1)
We already know the length of the pendulum, L=1.38 m, however we need to find its period of oscillation.
We know it makes N=441 oscillations in t=1090 s, therefore its frequency is
![f= \frac{N}{t}= \frac{441}{1090 s}=0.40 Hz](https://tex.z-dn.net/?f=f%3D%20%5Cfrac%7BN%7D%7Bt%7D%3D%20%5Cfrac%7B441%7D%7B1090%20s%7D%3D0.40%20Hz%20%20)
And its period is the reciprocal of its frequency:
![T= \frac{1}{f}= \frac{1}{0.40 Hz}=2.47 s](https://tex.z-dn.net/?f=T%3D%20%5Cfrac%7B1%7D%7Bf%7D%3D%20%5Cfrac%7B1%7D%7B0.40%20Hz%7D%3D2.47%20s%20%20)
So now we can use eq.(1) to find the gravitational acceleration of the planet:
Answer:
d = 4 d₀o
Explanation:
We can solve this exercise using the relationship between work and the variation of kinetic energy
W = ΔK
In that case as the car stops v_f = 0
the work is
W = -fr d
we substitute
- fr d₀ = 0 - ½ m v₀²
d₀ = ½ m v₀² / fr
now they indicate that the vehicle is coming at twice the speed
v = 2 v₀
using the same expressions we find
d = ½ m (2v₀)² / fr
d = 4 (½ m v₀² / fr)
d = 4 d₀o
Answer:
The force applied to the surface is 9 kilo Newton.
Explanation:
While jumping on the surface the player applies the force that is equal to its weight on the surface.
The mass of the player is given as 90 kg.
Force applied by the player = weight of the player
Force applied by the player = m × g
Where m is the mass of the player and g is acceleration due to gravity
Force applied by the player = 90 × 9.8
Force applied by the player = 882 Newton
Expressing your answer to one significant figure, we get
Force applied by the player =0. 9 kilo Newton
The force applied to the surface is 0.9 kilo Newton.
It is an imaginary transformer which has no core loss, no ohmic resistance and no leakage flux. The ideal transformer has the following important characteristic. The resistance of their primary and secondary winding becomes zero. The core of the ideal transformer has infinite permeability.