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Lapatulllka [165]
3 years ago
12

. Suppose that the displacement of an object is related to time according to the expression: x(t) = B t3 . Using dimensional ana

lysis, find the dimensionality of B.
Physics
1 answer:
-Dominant- [34]3 years ago
6 0

Answer:

The dimensionality of B is <em>length</em> per cubic <em>time</em>.

Explanation:

Units for displacement and time are <em>length</em> [L] and <em>time</em> [T], respectively. Then, formula can be tested for dimensional analysis as follows:

[L] = B\cdot [T]^{3}

Now, let is clear B to determine its units:

B = \frac{[L]}{[T]^{3}}

The dimensionality of B is <em>length</em> per cubic <em>time</em>.

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A circuit consists of a 171- resistor and a 0.158-H inductor. These two elements are connected in series across a generator that
kotykmax [81]

Answer:

a ) I= 1.635-i0.0021 b) ∅=   -0.074

Explanation:

a) reactive impeadance= 2πfL

                                 =2(3.14)(147)(0.158)

                                 =145.86 Ω

Z= 171+j145.86

I=V/Z

I=278/(171+j145.86)

I= 1.635-i0.0021

b) ∅=inv.tan (-0.0021/1.635)

 ∅=-0.074

 

6 0
3 years ago
calculate the diameter of the fifteen orbit of the hydrogen atom if the diameter of the innermost orbit is 1.06 A
mash [69]
We know, dₓ α n² d₁

For n = 15 (15th Orbit)

It would be: d₁₅ = 15² * 1.06

d₁₅ = 238.5 A

In short, Your Answer would be: 238.5 A

Hope this helps!
8 0
4 years ago
Read 2 more answers
Find the magnitude of this<br> vector:
xeze [42]

Answer: = 25. 5 m

Explanation:

  • 2-D vectors can be solved using the Pythagorean theorem:  
  • a^{2} +b^{2} =c^{2}
  • The hypotenuse, or longest side is not given and that is what must be solved for
  • Direction can be omitted as the question only asks for magnitude
  • Magnitude: is the distance or quantity in which an object moves during motion

Solve for C using Pythagorean theorem:

1. \sqrt{a^{2}+b^{2}  }=c

2.  \sqrt{22.2 m ^{2} +12.6m^{2} } =c

3. 25.52646 m= c

  • round to lowest number of significant digits  when dividing and multiplying
  • rounded to 3 significant digits

∴ Magnitude of the vector is 25.5 m

3 0
2 years ago
Can someone please help me on this!!!
elena-s [515]

Answer:

IDK

Explanation:

IDK

6 0
3 years ago
A centrifuge accelerates uniformly from rest to 15000 rpm in 330 s . Through how many revolutions did it turn in this time?
eduard

Answer:

The number of revolutions turned by the centrifuge is 8250 revolutions.

Explanation:

Given;

number of revolution per minutes, ω = 15000 rpm

time of  motion, t = 330 s = 5.5 minutes

The number of revolutions turned by the centrifuge is given by;

N = \frac{1500 \ Rev}{minutes} *5.5 \ minutes\\\\N = 8250 \ revolutions

Therefore, the number of revolutions turned by the centrifuge is 8250 revolutions.

4 0
3 years ago
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