Where are the following awnsers?
The simplest way to do this is to set up equivalent fractions, like this-

=

Solve for x by using cross multiplication.
40*2.2= 88
1*x=88
x=88
Therefore, the boy weighs 88lbs.
Answer:
The appropriate solution is "2.78 mm".
Explanation:
Given:

or,



or,

As we know,
Fringe width is:
⇒ 
hence,
Separation between second and third bright fringes will be:
⇒ 


or,

Answer:
By conservation of energy, it can climb up to a height equal to that it went down before. However, due to the friction in the machines, the total mechanical energy of the roller coaster will decrease. As a result, the first "hill" of many roller coasters are the highest, but the followings will have decreasing heights.
Explanation: