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Llana [10]
3 years ago
15

4. A moped travels 20 kilometers in 30 minutes. Calculate its average speed in km/h?

Physics
2 answers:
Nikolay [14]3 years ago
7 0
Average speed = 40km/h
Ann [662]3 years ago
5 0

Answer:

\boxed{Average \: speed = 40 km/h}

Explanation:

Distance travelled = 20 km

Time taken = 30 min

= \frac{30}{60} h

= \frac{1}{2} h

Average \: speed = \frac{Distance \: travelled}{Time \: taken} \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{20}{ \frac{1}{2} } \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 20 \div  \frac{1}{2} \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 20 \times 2 \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 40km/h

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nirvana33 [79]

To develop this problem we will apply the concepts related to angular kinematic movement, related to linear kinematic movement. Linear velocity can be described in terms of angular velocity as shown below,

v = r\omega \rightarrow \omega = \frac{v}{r}

Here,

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Our values are

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r = \frac{d}{2} = \frac{120*10^{-3}}{2} = 0.06m

Replacing to find the angular velocity we have,

\omega = \frac{6m/s}{0.06m}

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Convert the units to RPM we have that

\omega = 100rad/s (\frac{1rev}{2\pi rad})(\frac{60s}{1m})

\omega = 955.41rpm

Therefore the angular speed of the wheels when the scooter is moving forward at 6.00 m/s is 955.41rpm

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faltersainse [42]

<u>Answer:</u>

<em>They are a lot of religions and faiths across the globe. </em>

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Some of them are:

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There are two types of waves:

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So, these types of waves are called longitudinal waves.


2. d. a medium

There are two types of waves:

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GuDViN [60]

Answer:

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Here we will find frequency and period should be in second, here given: 0.05 seconds

using the formula:

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\boxed{frequency =20}

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