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3 years ago

4. A moped travels 20 kilometers in 30 minutes. Calculate its average speed in km/h?

Physics

2 answers:

Nikolay [14]3 years ago

7 0

Average speed = 40km/h

Ann [662]3 years ago

5 0

Answer:

$\boxed{Average \: speed = 40 km/h}$

Explanation:

Distance travelled = 20 km

Time taken = 30 min

= $\frac{30}{60}$ h

= $\frac{1}{2}$ h

$Average \: speed = \frac{Distance \: travelled}{Time \: taken} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{20}{ \frac{1}{2} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \div \frac{1}{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \times 2 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 40km/h$

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aliya0001 [1]

Answer:

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Explanation

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3 years ago

Energy conservation

balandron [24]

Answer:

7.328m/s

Explanation:

Given parameters:

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Unknown:

Initial velocity of ball = ?

Solution:

To solve this problem, we are going to employ the appropriate motion equation.

We must understand that this fall occurs in the presence of gravity;

V = U + 2gH

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g is the acceleration due to gravity

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3 years ago

Which should be done in case of a laboratory accident?

stich3 [128]

Tell your instructor or teacher

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3 years ago

During a tornado in 2008 the Peachtree Plaza Westin Hotel in downtown Atlanta suffered damage. Suppose a piece of glass dropped

Darina [25.2K]

Answer:

Time = t = 6.62 s

Explanation:

Given data:

Height = h = 215 m

Initial velocity = $v_{i}$ = 0 m/s

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Time = t = ?

According to second equation of motion

$h = v_{i}t + \frac{1}{2}gt^{2}$

As initial velocity is zero, So the first term of right hand side of above equation equal to zero.

$h = \frac{1}{2}gt^{2}$

t² = $\frac{2h}{g}$

t = $\sqrt{\frac{2h}{g} }$

t = $\sqrt{\frac{(2)(215) }{9.8} }$

t = 6.62 s

3 0

3 years ago

Three equal point charges, each with charge 1.15 μCμC , are placed at the vertices of an equilateral triangle whose sides are of

julsineya [31]

Answer:

$U=50.96J$

Explanation:

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U=1/4π∈₀×(q₁q₂/r)

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Substitute given values

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8 0

3 years ago