Answer:
There are 5 main conditions of the alveoli for proper gaseous exchange to in the lungs.
Explanation
Alveoli is found in the lungs of mammals, birds and reptiles. It is the part of the lungs where gaseous exchange really occurs.
Alveoli has a shape of that of balloon but indeed smaller than the real balloon. It allows the passage of oxygen and carbon dioxide
The five main conditions includes:
- The Alveoli must have large surface to volume ratio which increase the gases that could be exchanged
- The wall must be thin. This can shorten diffusion distance.
- Alveoli must be very moist so that oxygen and carbon dioxide can pass through the solution
- Alveoli must be well supplied with blood
- Alveoli must be permeable
Answer:
7.328m/s
Explanation:
Given parameters:
height of table = 0.68m
final velocity of the ball = 6m/s
Unknown:
Initial velocity of ball = ?
Solution:
To solve this problem, we are going to employ the appropriate motion equation.
We must understand that this fall occurs in the presence of gravity;
V = U + 2gH
Where;
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity
H is the height of the pool table
Since U is the unknown, let us make it the subject of the expression;
U = V - 2gH
U = 6 - (2 x 9.8 x 0.68) = 7.328m/s(deceleration)
Tell your instructor or teacher
Answer:
Time = t = 6.62 s
Explanation:
Given data:
Height = h = 215 m
Initial velocity =
= 0 m/s
gravitational acceleration = g = 9.8 m/s²
Time = t = ?
According to second equation of motion

As initial velocity is zero, So the first term of right hand side of above equation equal to zero.

t² = 
t =
t = 
t = 6.62 s
Answer:

Explanation:
The electrostatic potential energy for pair of charge is given by
U=1/4π∈₀×(q₁q₂/r)
Hence for a system of three charges the electrostatic potential energy can be found by adding up the potential energy for all possible pairs or charges.For three equal charges on the corners of an equilateral triangle,the electrostatic potential energy is given by:
U=1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)
U=3×1/4π∈₀×(q²/r)
Substitute given values
So