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mr Goodwill [35]
2 years ago
6

If I start with an 30 gram sample of Plutonium-244, how many grams would be left of Plutonium-244 after 1 half life

Physics
1 answer:
andriy [413]2 years ago
4 0

Answer:

15 g

Explanation:

Given,

Plutonium-244 = 30 g

We have to find the gram of Plutonium-244 left after 1 half-life.

We know that the half-life of a radioactive isotope is constant. The half-life of a Radioactive isotope does not depend on the initial amount of isotope.

Now,

After 1 half-life

Plutonium-244 left = \dfrac{30}{2}

                               = 15 g

Hence, 15 g of the Plutonium-244 will be left after 1 half-life.

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What is the time constant of a series circuit where the capacitor is 0.330μF and the resistor is 10Ω ?
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Answer:

\tau=3.3*10^{-6}s

Explanation:

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C*\frac{dV}{dt}+\frac{V}{R}=0

This is a separable first order differential equation, let's solve it step by step:

Express the equation this way:

\frac{dV}{V}=-\frac{1}{RC}dt

integrate both sides, the left side will be integrated from an initial voltage v to a final voltage V, and the right side from an initial time 0 to a final time t:

\int\limits^V_v {\frac{dV}{V} } =-\int\limits^t_0 {\frac{1}{RC} } \, dt

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ln(\frac{V}{v})=e^{\frac{-t}{RC} }

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V(t)=ve^{-\frac{t}{RC} }

Where the term RC is called time constant and is given by:

\tau=R*C=10*(0.330*10^{-6})=3.3*10^{-6}s

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2 years ago
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anyanavicka [17]
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pishuonlain [190]

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AURORKA [14]

Answer:

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Explanation:

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The complete sentence is:

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