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mr Goodwill [35]
2 years ago
6

If I start with an 30 gram sample of Plutonium-244, how many grams would be left of Plutonium-244 after 1 half life

Physics
1 answer:
andriy [413]2 years ago
4 0

Answer:

15 g

Explanation:

Given,

Plutonium-244 = 30 g

We have to find the gram of Plutonium-244 left after 1 half-life.

We know that the half-life of a radioactive isotope is constant. The half-life of a Radioactive isotope does not depend on the initial amount of isotope.

Now,

After 1 half-life

Plutonium-244 left = \dfrac{30}{2}

                               = 15 g

Hence, 15 g of the Plutonium-244 will be left after 1 half-life.

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A car is being driven at a rate of 60 ft/sec when the brakes are applied. The car decelerates at a constant rate of 19
Hunter-Best [27]

The car will take 300 m before it stops due to applying break.

<h3>What's the relation between initial velocity, final velocity, acceleration and distance?</h3>
  • As per Newton's equation of motion, V² - U² = 2aS
  • V= final velocity velocity of the object, U = initial velocity velocity of the object, a= acceleration, S = distance covered by the object
  • Here, U = 60 ft/sec, V = 0 m/s, a= -6 ft/sec²
  • So, 0² - 60² = 2×6× S

=> -3600 = -12S

=> S = 3600/12 = 300 m

Thus, we can conclude that the distance covered by the car is 300 m before it stopped.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: A car is being driven at a rate of 60 ft/sec when the brakes are applied. The car decelerates at a constant rate of 6 ft/sec². How long will it take before the car stops?

Learn more about the Newton's equation of motion here:

brainly.com/question/8898885

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7 0
2 years ago
What is electricity
irina [24]
D I know this is right
5 0
3 years ago
A parallel-plate air capacitor is made from two plates 0.210 m square, spaced 0.815 cm apart. it is connected to a 120 v battery
GuDViN [60]

Answer:

at the beginning: 2.3\cdot 10^{-10} F

when the plates are pulled apart: 1.1\cdot 10^{-10} F

Explanation:

The capacitance of a parallel-plate capacitor is given by

C=k \epsilon_0 \frac{A}{d}

where

k is the relative permittivity of the medium (for air, k=1, so we can omit it)

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the permittivity of free space

A is the area of the plates of the capacitor

d is the separation between the plates

In this problem, we have:

A=0.210 m^2 is the area of the plates

d=0.815 cm=8.15\cdot 10^{-3} m is the separation between the plates at the beginning

Substituting into the formula, we find

C=(1)(8.85\cdot 10^{-12}F/m)\frac{0.210 m^2}{8.15\cdot 10^{-3} m}=2.3\cdot 10^{-10} F

Later, the plates are pulled apart to d=1.63 cm=0.0163 m, so the capacitance becomes

C=(1)(8.85\cdot 10^{-12}F/m)\frac{0.210 m^2}{0.0163 m}=1.1\cdot 10^{-10} F

4 0
3 years ago
If two 100 ohms resistors are placed in series, their total resistance is what?
Sindrei [870]

Answer:

add the Resistance

2(100)= 200

2) 200 ohms

3 0
3 years ago
What energy comes from swinging a bat
hjlf

Answer:

Kinetic Energy

Explanation:

The potential energy is being converted into kinetic energy. The hitter has struck the ball transferring the kinetic energy from the swinging bat to the ball.

8 0
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