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yawa3891 [41]
3 years ago
7

What is the answer this is my exam help pl

Mathematics
1 answer:
Tanya [424]3 years ago
6 0
If you use PEDMAS you have the correct answer. Do the exponents first and you get -8 +absolute value of 7 (which is just 7 absolute value is always positive) and then subtract the product of 4 and 2 which is 8.
so I have -8+7-8 =-9
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Consider two vectors A and B A=14i and B= -4i+8j
DaniilM [7]
Assuming \mathbf a,\mathbf b\in\mathbb R^3, you have

\mathbf a\cdot\mathbf b=(14)(-4)+(0)(8)=-56

so

((\mathbf a\cdot\mathbf b)\,\mathbf i)\cdot\mathbf a=(-56\,\mathbf i)\cdot(14\,\mathbf i)=(-56)(14)=-784

Next,

\mathbf a+\mathbf b=(14\,\mathbf i)+(-4\,\mathbf i+8\,\mathbf j)=10\,\mathbf i+8\,\mathbf j

Then

(\mathbf a+\mathbf b)\times\mathbf b=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\10&8&0\\-4&8&0\end{vmatrix}=112\,\mathbf k

((\mathbf a+\mathbf b)\times\mathbf b)\times\mathbf k=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&112\\0&0&1\end{vmatrix}=\mathbf 0
4 0
4 years ago
The area of a rectangle is represented by the expression 6x³y5. Which of the following could be the
oee [108]

The length and width of the rectangle are: 2x^2y^2 , 3xy^3

<h3>What is the area of the rectangle?</h3>

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

The area of a rectangle is represented by the expression 6x^3y^5.

The area of the rectangle = 2x^2y^2 \times 3xy^3

                                          = 6x^3y^5

So, the length and width of the rectangle are: 2x^2y^2 , 3xy^3

Learn more about the area;

brainly.com/question/1658516

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7 0
2 years ago
If a football field is 100 yards long and 54 yard wide and what is the area in perimeter of that football filed
OlgaM077 [116]

Answer:

5400

Step-by-step explanation:

you would measure the length and width. Multiply the length by the width to get the area, and add twice the length to twice the width to get the perimeter

7 0
3 years ago
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Answer:

x = 8, y = 2

Step-by-step explanation:

Multiply the second equation by -2:

x + 6y = 20

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Add the equations and simplify:

-x = -8

x = 8

Plug x = 8 back into the first equation and solve for y:

8 + 6y = 20

6y = 12

y = 2

6 0
3 years ago
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I prefer to use fractions for some irrational numbers.

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4 years ago
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