Answer:
a. 4
b. 1/4
c. 16
d. 1/9
e. 4/9
f. 9/16
Step-by-step explanation:
The ratio of the areas is the square of the ratio of the lengths of the sides.
a. Triangles G and F
Select a side in triangle G and the corresponding side in triangle F:
side in F: 10
corresponding side in G: 5
ratio of lengths of F to G = 10/5 = 2
ratio of areas of G to F: (2)^2 = 4
b. Triangles G and B
Select a side in triangle G and the corresponding side in triangle B:
side in G: 5
corresponding side in B: 5/2
ratio of lengths of B to G = (5/2)/5 = 1/2
ratio of areas of B to G: (1/2)^2 = 1/4
c. Triangles B and F
Select a side in triangle B and the corresponding side in triangle F:
side in B: 5/2
corresponding side in F: 10
ratio of lengths of F to B = 10/(5/2) = 4
ratio of areas of F to B: (4)^2 = 16
Do the same for the other 3 pairs of triangles.
The answers are:
d. 1/9
e. 4/9
f. 9/16
Answer: 
Step-by-step explanation:
1. You know that:
- The roped-off area whose width is represented with <em>x,</em> it is created around a rectangular museum.
- The dimensions of the rectangular museum are: 30 ft by 10 ft.
- The combined area of the display and the roped-off area is 800 ft².
2. The area of the rectangular museum can be calculated with:
Where 
is the lenght and 
is the width.
You have that the lenght and the width in feet are:
3. Let's call 
the width of the roped-off area. Then, the combined area is:
Where
4. Substitute values and simplify. Then:
Answer:
(-4, 6), (0, 2), (4, -2)
Step-by-step explanation:
You just need to guess and check.
(-4,6) → -4 + 6 = 2 ✔
(0,2) → 0+2 = 2 ✔
(4,2) → 4 + 2 = 6
(4, -2) → 4 - 2 = 2 ✔
(-4,-6) → -4 - 6 = -10
The correct answer is the second list (-4, 6), (0, 2), (4, -2)
Answer:
DOnt know
Step-by-step explanation:
dont know
Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
