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cupoosta [38]
3 years ago
10

Two-ninths of h algebraic expression translate

Mathematics
1 answer:
Tom [10]3 years ago
6 0
2/9 of H?... , um I think
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HELP PLEASE <br> I need to know a line that goes through (17,1/3) and (25 1/2,1/2) aka the slope
konstantin123 [22]

Answer:

0.16/8.5

Step-by-step explanation:

so to get the slope use (Y2-Y1) over (X2-X1)

this means that the formula is

1/2-1/3

---------

25.5- 17

6 0
3 years ago
The rate for one unit of a given quantity is called a(n)
asambeis [7]
<span>The rate for one unit of a given quantity is called a u</span>nit rate. 
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3 years ago
What is the perimeter?
Vladimir79 [104]

Answer:

Perimeter = 22 units

Area = 30 units squared

Step-by-step explanation: To find the perimeter of this figure, add the lengths of the rectangle's four sides (5+6+5+6=22). To find the area of this figure, multiply the length and width of the rectangle (5x6=30).

5 0
2 years ago
Joshua is going to mow lawns during his summer break. The graph in the figure shows a linear relationship between the number of
inessss [21]

Answer:

we need the graph to answer the question

Step-by-step explanation:

we wont know much he makes each week without the graph

7 0
3 years ago
Identify the x-intercepts of the function below f(x)=x^2+12x+24
damaskus [11]

<u>ANSWER:  </u>

x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

<u>SOLUTION:</u>

Given, f(x)=x^{2}+12 x+24 -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here, for (1) a = 1, b= 12 and c = 24

X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}

\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}

Hence the x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

8 0
3 years ago
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