Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
Answer:
Your answer would be B: $25.20
24 x 5% is 1.2
$24 + 1.2 is 25.2
Step-by-step explanation:
This is the standard for of seven hundred (700) thirty (30) one (1) :
Answer: 731
Answer:
4+6=10
Step-by-step explanation:
Answer:
I think its 300
but wouldn't that be like a 2 digit number like 30? scince they are only 10 blocks 10 + 10 + 10 (3×10= 30)
If you dont understand just coment.