2 years ago

Solve the equation. 15x^2-29x-a^2=0

Mathematics

1 answer:

Lelechka [254]2 years ago

6 0

Answer:

IDK and Im sorry if I wasted ur time

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sergiy2304 [10]

Answer:

$\frac{ {b}^{10} }{ 81 {a}^{2} }$

Step-by-step explanation:

$(9ab^{-5})^{-2} \\ \\ = {9}^{ - 2} {a}^{ - 2} {b}^{ - 5( - 2)} \\ \\ = {9}^{ - 2} {a}^{ - 2} {b}^{10} \\ \\ = \frac{ {b}^{10} }{ {9}^{2} {a}^{2} } \\ \\ \huge = \frac{ {b}^{10} }{ 81 {a}^{2} }$

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2 years ago

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kondaur [170]

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3 years ago

Use the distributive property to expand the linear expression. 3(4x + 3) A) 3 4 B) 12x + 6 C) 12x + 9 D) -3 4

kipiarov [429]

Answer:

Step-by-step explanation:

The distributive property: <em>a(b + c) = ab + ac</em>.

$3(4x+3)=(3)(4x)+(3)(3)=12x+9$

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2 years ago

<img src="https://tex.z-dn.net/?f=3%2F5%20of%205%2F9%5C%5C" id="TexFormula1" title="3/5 of 5/9\\" alt="3/5 of 5/9\\" align="absm

pychu [463]

Answer:

<u>⅓</u>

<h2>Step-by-step explanation:</h2>

$\frac{5}{9} \times \frac{3}{5}$

$= \frac{1}{3} \times \frac{1}{1}$

$= \frac{1}{3}$

<h2>Checking:</h2>

$\frac{1}{3} \div \frac{3}{5}$

$= \frac{1}{3} \times \frac{5}{3}$

$= \frac{5}{9}$

#CarryOnLearning

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2 years ago

Read 2 more answers

Can someone please help me with these will give brainliest

rodikova [14]

1. multiply 1.6 by 2, resulting in 3.2
2. p < 4
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2 years ago

Solve the equation. 15x^2-29x-a^2=0​

Solve the equation. 15x^2-29x-a^2=0