So column A needs to all be the same multiples of 4 so 4•3 is 12 and so other multiples need to be placed
Answer:
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Step-by-step explanation:
Answer:
Square root of 4 is 2
so 1+
=4
frac{[1+sqrt{2x-1]}^2 }{4}=3
so 1+sqrt{2x-1]}^2=12
so 1+sqrt{2x-1}=V12
sqrt{2x-1}=V12-1
2x-1=(V12-1)^2=12-2V12+1=13-2V12
2x=13+1-2V12
2x=14-2V12
x=7-V12
x=7-2V3
I put an attachment to explain better
Step-by-step explanation:
Answer:
A = (5s^2t - 9st) (3t + 1)
Step-by-step explanation:
(5s^2 - 9s) (3t^2 + t)
= 15s2t^2 + 5s^2t - 27st^2 - 9st
= 5s2t (3t + 1) - 9st (3t + 1)
= ( 5s^2t - 9st) (3t+1)
Answer: (3,4)
Each input can only have one output for a function
The other pairs give a different output for the input so that would make it a relation not a function.