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atroni [7]
2 years ago
11

Abcdefgh is a regular octagon. M is a point on the line dh. N is a point on the line fm. The line dn and fm are perpendicular. P

rove that triangles fhm and dfp are congruent

Mathematics
1 answer:
Aloiza [94]2 years ago
3 0

ΔFHM and ΔDFP by addition to ΔMOF and ΔPDO respectively gives

ΔHOP and ΔDOF, which are congruent.

Response:

  • ΔFHM ≅ ΔDFP by transitive property of equality

<h3>Methods used to prove that the two triangles are congruent</h3>

Based on the properties of a regular octagon, the diagonals DH and BF

of a regular octagon are perpendicular, and they bisect each other,

given that the length of half the diagonal represent the radius of the

circumscribing circle.

Therefore;

∠NFP ≅ ∠NFP by reflexive property

∠PNF ≅ ∠MOF all right angles are congruent

ΔMOF is similar to ΔPNF by Angle-Angle AA similarity postulate.

∠OMF ≅ ∠DMN by reflexive property

Therefore;

ΔDMN is similar to ΔMOF by AA similarity postulate.

Similarly, we have;

ΔDMN ~ ΔPDO by AA similarity postulate;

Therefore;

ΔPDO is similar to ΔOMF by transitive property

∠ODP ≅ ∠OFM by CASTC, Corresponding Angles of Similar Triangle are Congruent.

OD = OF distance from center to the vertex of a regular octagon are

equal to the radial length of the circumscribing circle and are therefore

equal.

Therefore;

ΔPDO ≅ ΔOMF by Angle-Side-Angle ASA congruency rule

ΔPDO = ΔOMF definition of congruency

  • ΔHOF ≅ ΔDOF by Side-Angle-Side, SAS, congruency rule

ΔHOF = ΔDOF

ΔFHM = ΔHOF - ΔOMF subtraction property

Similarly

ΔDFP = ΔDOF - ΔPDO = ΔHOF - ΔOMF = ΔFHM by substitution property

ΔDFP = ΔFHM

ΔFHM = ΔDFP by symmetric property.

Therefore;


  • <u>ΔFHM ≅ ΔDFP by definition of congruency</u>

Learn more about the properties of a regular octagon here:

brainly.com/question/4503941

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Answer:

Step-by-step explanation:

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Answer A is not correct as stated, but would be correct if we were to replace "the y-coordinates" with "the x-coordinates."  

Answer C would be correct if and only if we write y = x^2 - 5x - 1.

6 0
3 years ago
X, Y and Z form the vertices of a triangle. XY = 12.4m, XZ = 10.4m and YZ = 8.7m. Find the angle ∠ YXZ rounded to 1 DP.
sweet-ann [11.9K]

Answer:

43.8°

Step-by-step explanation:

Applying,

Cosine rule,

From the diagram attached,

x² = y²+z²-2yxcos∅.................... Equation 1

where ∅ = ∠YXZ

Given: x = 8.7 m, y = 10.4 m, z = 12.4 m

Substitute these values  into equation 1

8.7² = 10.4²+12.4²-[2×10.4×12.4cos∅]

75.69 = (108.16+153.76)-(257.92cos∅)

75.69 = 261.92-257.92cos∅

collect like terms

257.92cos∅ = 261.92-75.69

257.92cos∅ = 186.23

Divide both sides by the coefficient of cos∅

cos∅ = 186.23/257.92

cos∅ = 0.722

Find the cos⁻¹ of both side.

∅ = cos⁻¹(0.7220)

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∅ = 43.8°

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Answer:

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