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Cloud [144]
3 years ago
8

Help

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
7 0

Answer:

x=5

Step-by-step explanation:

(8x-8)3/2=64

(24x-8)/2=64 -You are distributing the three

12x-4=64 -You divide the whole thing by two

12x=60 -You subtract the four from both sides

x=5 - You divided the twelve from both sides

Hope this helps!

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prakriti needs $3500 for high study in america after see.if $1=105Nrp if bank charge 3% commission how much nepali rupee should
timofeeve [1]

Answer:

356475Nrp

Step-by-step explanation:

$1=105Nrp

$3500=105×3500Nrp

=367500Nrp

Now,

Bank charges 3% commission

therefore, 3% of 367500Nrp

=3/100×367500Nrp

=11025Nrp

Then,

Required money =367500Nrp-11025Nrp

=356475Nrp

3 0
3 years ago
3,408 divided by 41 <br><br> Explanation in traditional method<br><br><br><br> 52 POINTS PLS HELP
Furkat [3]

Answer:

83.1219512195

Step-by-step explanation:

Hope this helps!

7 0
2 years ago
Read 2 more answers
An airplane spots the floating debris at an angle of depression of 15 degrees. If the plane is at an altitude of 3000. Feet, wha
hodyreva [135]

Answer:

11196.15 km

Step-by-step explanation:

Consider the attached diagram

If the Airplane is at point A and the floating debris at point C, we want to determine the horizontal distance |AB| before they fly over it.

Using trigonometry

Tan \alpha =\frac{Opposite}{adjacent} \\Tan 15 =\frac{3000}{|AB|}

Cross multiply

|AB|X Tan 15 =3000

|AB| = \frac{3000}{Tan 15} =11196.15 km

Therefore, the horizontal distance |AB| before they fly over it is 11196.15 km

6 0
3 years ago
A major department store chain is interested in estimating the mean amount its credit card customers spent on their first visit
sergiy2304 [10]

Answer:

95% Confidence interval: (39.43, 61.58)

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = $50.50

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation = 20

95% Confidence interval:

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.05} = \pm 2.1447  

=50.50 \pm 2.1447(\dfrac{20}{\sqrt{15}} ) \\\\= 50.50 \pm 11.0751 \\= (39.4249,61.5751)\\\approx (39.43, 61.58)  

95% Confidence interval: (39.43, 61.58)

8 0
3 years ago
Determine the value of −14.1 × (-7.33)
Darya [45]

Answer:

Multiply -14.1 by -7.33.103.353     ?

Step-by-step explanation:

Sorry I'm not very good at math hope this helps..

8 0
2 years ago
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