1 Simplify 7x+16+47x+16+4 to 7x+207x+20<span> 7x+20=x<span>7x+20=x</span></span>
2 Subtract 7x from both sides<span> 20=x-7x<span>20=x−7x</span></span>
3 Simplify <span>x-7x<span>x−7x</span></span> to <span>-6x<span>−6x</span></span>
<span>20=-6x<span>20=−6x</span></span>
4 Divide both sides by −6 -20/6=x
5 Simplify 20/6 to 10/3 -10/3=x
6 Switch sides
x=-10/3<span><span><span> </span></span></span>
The electrical resistance of a wire varies as its length and inversely as the square of the diameter.
R = (k*L)/(d^2)
where k = proportionality constant
Since the two wires have the same material, their proportionality constant is same.
Equating that
(R1*d1^2)/L1 = (R2*d2^2)/L2
Given that R1 = 10 ohms, d1 = 1.2 mm or 0.0012 m, L1 = 18 m, d2 = 1.5 mm or 0.0015 m, L2 = 27 m, and R2 is unknown.
Therefore
[10*(0.0012^2)]/18 = [R2*(0.0015^2)]/27
R2 = 9.6 ohms
Answer:
353.42 x 2 = $706.84
Step-by-step explanation:
Use long multiplication to evaluate.
