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ICE Princess25 [194]
3 years ago
15

Each year the local country club sponsors a tennis tournament. Plays starts with 128 participants. During each round, half of th

e players are eliminated. How many players remain after five rounds?
Mathematics
1 answer:
valkas [14]3 years ago
3 0

Answer:

128 divided by 2 for 5 times is your answer enjoy my.kiddo

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A rectangular auditorium seats 1344 people. The number of seats in each rows exceeds the number of rows by 20. Find the number o
Tasya [4]
Let the number of rows be x

rows = x
seats in each row = x + 20

total seats = 1344
x (x + 20) = 1344
x^2 + 20x - 1344 = 0
(x + 48)(x - 28) = 0
x = -48  (rejected, answer cannot be negative) or x = 28

Therefore,
x = 28 
x + 20 = 48


Check:
Row = 28
Numbers of seat per row = 28 + 20 = 48
28 x 48 = 1344 (Correct)
 
Ans:There are 48 seats per row 
8 0
3 years ago
Help please, you smart peoples ;-; Will give brainliest!
Norma-Jean [14]

Answer:

0.25

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Help quickly! A student wants to report on the number of movies her friends watch each week. The collected data are below:
max2010maxim [7]
1.The measure of center that is most appropriate for this situation is the MEDIAN. This is because, one of the number given is an outlier, that is, it is much greater than the rest of the given numbers. If the mean of the number given is calculated, it will be discovered that the mean value obtained is higher than most of the scores in the data set, thus,the mean is not a suitable measure of central tendency in this case.
2. To find the median of the given numbers, arrange them in a descending order and add the two numbers in the middle then divide the value by 2.
That is, 0, 0, 1, 1, 2, 2, 2, 14.
The two numbers in the middle is 1 and 2.
 Median = [1 + 2] / 2 = 3/2 = 1.5
Therefore, the median is 1.5
6 0
3 years ago
14.2 as a mixed number.
krek1111 [17]
I think its 14 1/5 (?)
7 0
3 years ago
Read 2 more answers
What are the solutions to the quadratic equation below x^2+20x+100=7​
aleksandrvk [35]

First you must have the quadratic equal to zero. In order to do this you must subtract 7 to both sides

x^2 + 20x + (100 - 7) = 7 - 7

x^2 + 20x + 93 = 0

Now you must find two numbers who's sum equals 20 and their multiplication equal 93

Are there any? NO!

This means that you have to use the formula:

\frac{-b±\sqrt{b^{2} - 4ac} }{2a}

In this case:

a = 1

b = 20

c = 93

\frac{-(20) plus/minus\sqrt{20^{2} - 4(1)(93)} }{2*1}

\frac{-20 plus/minus\sqrt{400 - 372} }{2}

\frac{-20 plus/minus\sqrt{28} }{2}

^^^We must simplify √28

√28 = 2√7

so...

\frac{-20 plus/minus 2\sqrt{7} }{2}

simplify further:

-10 plus/minus\sqrt{7

-10 + √7

or

-10 - √7

***plus/minus = ±

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
3 years ago
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