Name a radius of circle P.

Nicole is studying a two-way table. She has computed the relative frequencies by column for each cell Wrat characteristic of

Marianna [84]

Answer:

4th one

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The expression 4h−34h−3 factored is

Liula [17]

H=10 because u subtract 4 from30 and then divide by 3

6 0

3 years ago

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Given that Segment BE is 5 units, find the indicated measures for each

zalisa [80]

Answer:

The indicated measure of the length of AE = 5 units

Step-by-step explanation:

To determine:

What is the indicated measure of length?

Information Fetching and Solution Steps:

From this single diagram, it seems the indicated measure of length which we have to determine is the length of AE.

Given that Segment BE is 5 units. i.e. BE = 5 units

As the square has two equal diagonals AC and DB which meet at point E.

So, point E being the common mid-point of both diagonals.

As both of the diagonals of square are equal in length.

And the length of BE is 5 units, which is half the length of BD. It means the diagonal BD has a length of 10 units.

And since both diagonals AC and DB are equal in length, it means the length of AC must be 10 units.

Since, AC has the length of 10 units, it means the length of AE must be half of the length of AC. Thus, the indicated measure of the length of AE is 5 units.

Therefore, the indicated measure of the length of AE = 5 units

Keywords: square, diagonals, length, line segment

Learn more about square diagonals from brainly.com/question/628263

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6 0

3 years ago

Using distributive property what is 3(5 +6) =

Annette [7]

Answer:

3(5 +6) = 33

Step-by-step explanation:

3(5+6)

so first you multiply 3 by 5

which is 15

then you multiply 3 by 6

which is 18

and that remains as 15+18

which in total equals 33

7 0

3 years ago

Read 2 more answers

Find each graph, find (a) AB to the nearest tenth and (b) the coordinates of the midpoint of AB.

Rufina [12.5K]

Answer: AB≈10,8, C(-1;0,5).

Step-by-step explanation:

4.

$(-2,-2)\ \ \ \ (8,-6)\ \ \ \ \overline {AB}=?\\$

Equation of a straight line

$\boxed {\overline {AB}=\sqrt{(x_B+x_A)^2+(y_B-y_A)^2} }$

$x_A=-2\ \ \ \ x_B=8\ \ \ \ y_A=-2\ \ \ \ \ y_B=-6\\\\\overline{AB}=\sqrt{(8-(-2))^2+(-6-(-2))^2} \\\\\overline{AB}=\sqrt{(8+2)^2+(-6+2)^2} \\\\\overline{AB}=\sqrt{10^2+(-4)^2} \\\\\overline{AB}=\sqrt{100+16} \\\\\overline{AB}=\sqrt{116} \\\\\overline{AB}\approx10,8.$

5.

$(-2,-2)\ \ \ \ (0,3)\ \ \ \ the\ midpoint\ C\ of\ AB=?\\$

Line Midpoint Equation

$\boxed {C_x=\frac{X_A+X_B}{2} }}\ \ \ \boxed {C_y=\frac{Y_A+Y_B}{2} }$

$X_A=-2\ \ \ \ \ X_B=0\ \ \ \ \ Y_A==-2\ \ \ \ Y_B=3\\\\C_x=\frac{-2+0}{2} \\\\C_x=\frac{-2}{2} \\\\C_x=-1.\\\\C_y=\frac{-2+3}{2}\\\\C_y=\frac{1}{2}\\\\ C_y=0,5.\\\\Hence,\ \ \ \ C_{AB}(-1;0,5).$

8 0

2 years ago