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2 years ago

13

Given a set of data, what steps would you take to identify whether the data showed linear or exponential growth?

2 answers:

emmasim [6.3K]2 years ago

5 0

The very first thing to do to identify whether the data showed linear or exponential growth is to plot the data. By plotting the data, you are able to visualize the form or trend of your data. You can also see if your data trend forms a line. If it forms a line, it is linear. If your data shows somehow a rapid increasing magnitude of slope then, it is exponential.

vovangra [49]2 years ago

3 0

Answer:

Make sure that the x-values are spaced apart in equal intervals.

Determine whether the y-values increase by the same amount or by the same ratio.

Decide that the data is linear because the y-values increase by a common difference.

Decide that the data is exponential because the y-values increase by a ratio or factor.

Step-by-step explanation:

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Can you help me with this??

siniylev [52]

8*8 - 4*4*pi*(1/2) = 64 - 8*pi

6 0

3 years ago

A cuboid measures 6cm by 3cm by 2cm<br><br> Draw a net of the cuboid

Tresset [83]

Answer:

See attachment for cube

Step-by-step explanation:

Given

$Length = 6cm$

$Width = 3cm$

$Height = 2cm$

Required

The net of the cuboid

A cuboid has 6 faces.

The dimension of these faces are:

Length and Width; Length and Height;

Length and Width; Length and Height;

Width and Height; Width and Height;

This means that the faces will have the following dimensions:

6cm by 3cm; 6cm by 2cm

6cm by 3cm; 6cm by 2cm

3cm by 2cm; 3cm by 2 cm

Taking into account the above measurements and dimensions, you draw 6 faces, then join similar sides lengths.

<em>See attachment for net of the cuboid</em>

4 0

2 years ago

The general form of an parabola is 2x2−12x−3y+12=0 .

Murljashka [212]

Answer:

The standard form of the parabola is $(x-3)^2=4*\frac{3}{8}(y+2)$

Step-by-step explanation:

The standard form of a parabola is

$(x-h)^2=4p(y-k)$ .

In order to convert $2x^2-12x-3y+12=0$ into the standard form, we first separate the variables:

$2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y$

we now divided both sides by 2 to remove the coefficient from $2x^2$ and get:

$x^2-6x+6=\frac{3}{2}y$ .

We complete the square on the left side by adding 3 to both sides:

$x^2-6x+6+3=\frac{3}{2}y+3$

$x^2-6x+9=\frac{3}{2}y+3$

$(x-3)^2=\frac{3}{2}y+3$

now we bring the right side into the form $4p(y-k)$ by first multiplying the equation by $\frac{2}{3}$ :

$\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2$

and then we multiplying both sides by $\frac{3}{2}$ to get

$(x-3)^2=\frac{3}{2} (y+2)$ .

Here we see that

$4p=\frac{3}{2}$

$\therefore p=\frac{3}{8}$

Thus, finally we have the equation of the parabola in the standard form:

$\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}$

5 0

3 years ago

❗️10 points❗️<br> 22. match the expression with its name.

Hunter-Best [27]

Answer:

Quadratic trinomial

Step-by-step explanation:

It is a trinomial because it has 3 terms.

Quadratic means the highest exponent is 2.

6 0

3 years ago

What is the multiplicative inverse of 1 half

Lemur [1.5K]

The multiplicative inverse of 1 half would be <u>2</u>, or 2 over 1 (2/1).

Hope this helps. :)

8 0

3 years ago

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