2 years ago

Susan made some chocolate chip cookies. She found that three

Mathematics

1 answer:

wolverine [178]2 years ago

6 0

You never gave a question therefore there is no answer without a question

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Assuming Earth to be a sphere of radius 4000 miles, how many miles north of the Equator is City A, if it is 36° north from the E

vredina [299]

Answer:

2513 miles

Explanation:

$\sf Length \ of \ arc = \dfrac{\theta}{360} * 2\pi r$

Here given:

∅ = 36°

radius = 4000 miles

Insert following:

$\sf \rightarrow \dfrac{36}{360} * 2\pi (4000)$

$\sf \rightarrow 800\pi \ \ \ (in \ terms \ of \ \pi )$

$\sf \rightarrow 2513.3 \ \ (rounded \ to \ nearest \ tenth)$

$\sf \rightarrow 2513 \ \ (rounded \ to \ nearest \ mile)$

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Answer:

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Step-by-step explanation:

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Anon25 [30]

Good evening, Riley!

Used properties:

$\star~\boxed{\mathsf{a = \dfrac{ax}{x}, \ \ x\neq 0}}\\ \\ \\ \star~\boxed{\mathsf{\dfrac{\frac{a}{b}}{\frac{c}{d}} = \dfrac{ad}{bc}}}$

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So:

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FromTheMoon [43]

- 1/32 is your answer, hope this helped

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Find interquartile range for 3,4,5,6,7

lions [1.4K]

3, 4, 5, 6 and 7
Q 1= (3+4)/2=3.5
Q 2= (4+5)/2=4.5
Q 3=(5+6)/2=5.5
Interquartile range =Q3-Q1
=5.5-3.5
=2

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3 years ago

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