Question

Find the slope and y-intercept of the line that is parallel to y = -x - 3 and passes through the point (3, -2)

Answer 1

Use point slope formula y-y1=m(x-x1)
You are told that y=-x+3. This equation is of the form y=mx+b. Where m=-1. m is the slope. And you have a point (x1,y1) that is (3,-2). With all of this in mind, you then plug all of these details into the point slope formula y-y1=m(x-x1)

In point slope form, you have the following:


y-(-2)=-1(x-3).

To turn this into slope intercept form, simplify y-(-2) to get y+2 and distribute in the -1 to get:

y+2=-x+3

Subtract 2 from both sides to get

y=-x+1

In slope intercept form, the answer is
y=-x+1 and in point slope form, the answer is y+2=-x+3

Hope this helps!!!