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2 years ago

12

the width of a rectangle is 6inches less than twice it’s length. Find the dimension of the rectangle if it’s area is 108 square

inches

1 answer:

Sindrei [870]2 years ago

5 0

Answer:

Width = $12$ Length = $9$

Step-by-step explanation:

We have to first find an equations with the given variables:

$w = 2L - 6$

Now apply the area format:

$Length * Width$

Since the area is 108 square inches

$108 = l * w$

$108 = l(2l-6)$

$108 = l(2l) + l(-6)$

$108 = 2l^2 - 6l$

Simplify:

$(l-9) * (l+6) = 0$

Since no number can be negative

$w = 2*9(L)-6$

$w = 12$

$l=9$

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(a)

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(b)

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(c)

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Step-by-step explanation:

(a)

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(b)

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we get

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(c)

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we can use property of exponent

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we get

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(d)

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we get

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$(-5^{-3})^{-1}=(-5)^0$

we can use property

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