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Mashutka [201]
3 years ago
8

Answer answer it it it

Mathematics
1 answer:
lakkis [162]3 years ago
8 0

Answer:

May-June

Step-by-step explanation:

Notice that:

● during April-May period the Badminton memberships rate of increase is greather then Swimming's since the graph of Badminton is showing a faster increase.

● During June-July period, both functions are decreasing so this period does not satisfy our condition.

● During May-June The Swimming memberships growed faster than Badminton's so its rate of increase is greather than Badminton's.

● during August-September period, The swimming memeberships are increasing slower than Badminton's

So the answer is May-June

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A system of two linear inequalities is graphed as shown, where the solution region is shaded. Complete the sentences below by de
andrezito [222]

All the points  The point (-3.2), The point (-7.5), Point (2.-5), and The point (-14,6) is located in the solution region.

<h3>What is a graph?</h3>

A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.

When we plot all the points on the graph we can see that all the points The point (-3.2), The point (-7.5), Point (2.-5), and The point (-14,6) are located in the solution region.

Therefore all the points  The point (-3.2), The point (-7.5), Point (2.-5), and The point (-14,6) is located in the solution region.

To know more about graphs follow

brainly.com/question/25020119

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6 0
2 years ago
Help me<br>ans should be well explained :) ​
Slav-nsk [51]
551, it is too big of a number so it is the outlier. :)
5 0
3 years ago
Read 2 more answers
Given: measure of angle KJ = 124°, measure of IC =38°<br><br> Find: m∠CQJ, m∠LIJ.
VLD [36.1K]

Answer:

Part 1) m

Part 2) m

Step-by-step explanation:

Part 1) Find the measure of angle CQJ

we know that

The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite.

m

arc\ IK+arc\ CJ=360\°-(arc\ IC+arc\ KJ)

substitute the values

arc\ IK+arc\ CJ=360\°-(38\°+124\°)=198\°

m

Part 2) Find the measure of angle LIJ

step 1

Find the measure of angle IJL

we know that

The inscribed angle is half that of the arc it comprises.

m

substitute the values

m

step 2

Find the measure of angle ILJ

we know that

The measurement of the external angle is the semi-difference of the arcs it encompasses.

m

substitute the values

m

step 3

Find the measure of angle LIJ

Remember that the sum of the interior angles of a triangle must be equal to 180 degrees

In the triangle LIJ

m

substitute the values

m

m

3 0
3 years ago
Given: △CGF ,CG=GF=CF=and, KOPS is a square inside this triangle with one side on CF and its two vertices on CG and GF
shepuryov [24]

Answer:

  AKPOS/ACGF = 28√3 -48 ≈ 0.497423

Step-by-step explanation:

Let's assume the square is a unit square. Then the height of the triangle is ...

  1 +(√3)/2 = h

and half the base of the triangle is ...

  h/√3 = (√3)/3 +1/2 = b/2

The area of the triangle is the product of these:

  A = (1/2)bh

  = (2 +√3)/2 × (3 +2√3)/6

  = (6 +3√3 +4√3 +6)/12 = (12 +7√3)/12

So, the ratio of the area of the square to that of the triangle is the inverse of this, or ...

  (square area)/(triangle area) = 12/(12+7√3)

  (square area)/(triangle area) = 28√3 -48

8 0
3 years ago
If EF=2x-12, FG= 3x-15, and EG=23, find values of x, EF, and FG
velikii [3]

we have that


*-------------------------*--------------------------------*

E                            F                                     G


EF=2x-12

FG= 3x-15

EG=23


we know that


EF + FG = EG


so

[2x - 12] + [3x - 15] = 23 simplify

5x - 27 = 23 add 27 to both sides

5x = 50 divide both sides by 5

x = 10

EF=2x-12-------> EF=2*10-12-------> EF=8

FG= 3x-15------> FG=3*10-15------> FG=15



therefore


the answer part a) is

the value of x is 10


the answer part b) is

the value of EF is 8


the answer part c) is

the value of FG is 15

6 0
3 years ago
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