Answer:
2/8 < 7/8
Step-by-step explanation:
Since the denominators are the same, we compare the numerators
2<7 so
2/8 < 7/8
12/60 students chose science fiction
Approximately x/150 students prefer sf
60x = 1800
x = 30
30/150 students are assumed to prefer sf
30/150 = x/100
150x = 3000
x = 20
20/100 students are likely to prefer sf
Mr. Rodriguez made a reasonable estimate for the approximate percentage of students that prefer science fiction, because if 12/60 is equivalent to 30/150 which refers to the number of students who can be assumed to prefer science Fiction out of the whole school. Considering we need to identify what 30/150 as a percentage is, we can reduce it down to 1/5 to make I easier, then divide 1 by 5 to get .2
.2 as a percentage is 20%, so his inference was indeed reasonable.
(♥ω♥*)Brainliest Please(♥ω♥*)
<em><u>Question:</u></em>
Juan Invest $3700 In A Simple Interest Account At A Rate Of 4% For 15 Years. How Much Money Will Be In The Account After 15 Years?
<em><u>Answer:</u></em>
There will be $ 5920 in account after 15 years
<em><u>Solution:</u></em>
<em><u>The simple interest is given by formula:</u></em>

Where,
p is the principal
n is number of years
r is rate of interest
From given,
p = 3700
r = 4 %
t = 15 years
Therefore,

<em><u>How Much Money Will Be In The Account After 15 Years?</u></em>
Total money = principal + simple interest
Total money = 3700 + 2220
Total money = 5920
Thus there will be $ 5920 in account after 15 years
Do you have to keep going or only just one more number it seems to be going by 2’s 4,6,8,10,12 but I’m a little confused since it says it’s 9th grade work
Lets say that the two unknown integers are

and

.
We know the following things about

and

:


And, we want to find

.
To solve this, we'll use the expansion of the squared of the sum of any two inegers; this is expressed as:

So, given what we know about the unknown integers, the previous can be written as:

We can easily solve for

:
The answer is 168.
Another approach to solve the problem is, from the two starting equations, compute the values of

and

, which are 12 and 14, and directly compute their product; however, the approach described is more elegant.