Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan= 5/11.65
=23.23°
AC= km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
Answer:
Step-by-step explanation:
You want the distance traveled and the displacement after walking 17 m south and 13 m east.
<h3>Distance</h3>The distance traveled is the sum of the lengths of each leg of the trip:
17 m + 13 m = 30 m
You have traveled a distance of 30 m.
<h3>Displacement</h3>The displacement is the distance from your final position to your starting position. If you draw a diagram of the journey, you see the displacement is the hypotenuse of a right triangle with legs 17 m and 13 m. The Pythagorean theorem can help you find this length:
h = √(a² +b²)
h = √(17² +13²) = √(289 +169) = √458 ≈ 21.401
At the end of your walking, you are 21.4 m from where you started.
Answer:
$13286.02
Step-by-step explanation:
100 + 8 = 108
108 / 100 = 1.08
6154 x = $13286.02