Answer:
![X = \left[\begin{array}{cccc}12&-24&8&16\end{array}\right]](https://tex.z-dn.net/?f=X%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D12%26-24%268%2616%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
A matrix is given by
Now, we have to find the matrix X if
⇒ X = 2A
Now, multiplication of a constant with a matrix means multiplication with that constant with all the terms of the matrix.
So,
⇒
(Answer)
Answer:
Number of students in vans =15 and bus =46
Step-by-step explanation:
use variables for the vans and buses
let x= vans and y=buses
Now solve the 2 equations simultaneously
<em><u>remember</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>equations</u></em>
6x+7y=412..........1
6x+9y=504.........2
make x the subject of one equation
and label it equation 3
6x=412—7y

subs 3 into 2





subs 4 into 1





Therefore there are 15 students in each van and 46 students in each bus.
<h3>
Answer: B) Only the first equation is an identity</h3>
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I'm using x in place of theta. For each equation, I'm only altering the left hand side.
Part 1
cos(270+x) = sin(x)
cos(270)cos(x) - sin(270)sin(x) = sin(x)
0*cos(x) - (-1)*sin(x) = sin(x)
0 + sin(x) = sin(x)
sin(x) = sin(x) ... equation is true
Identity is confirmed
---------------------------------
Part 2
sin(270+x) = -sin(x)
sin(270)cos(x) + cos(270)sin(x) = -sin(x)
-1*cos(x) + 0*sin(x) = -sin(x)
-cos(x) = -sin(x)
We don't have an identity. If the right hand side was -cos(x), instead of -sin(x), then we would have an identity.
Answer:

Step-by-step explanation:
Let x be equal to the number.
We can use what the question gives us to directly form a mathematical statement. When you multiply it by 3 (3x) and then subtract 10 (3x-10) you will get a number less than 5 (<5). Using this, our mathematical statement would look like this:

To find the range of possible values, we must solve the inequality and isolate x.

Add 10 to both sides

Divide both sides by 3

I hope this helps!
Answer:4 dozens of video games would cost $1956
Step-by-step explanation:
An electronic store prices 3 dozen video games at a total of 1467. A dozen of video games is 12. Therefore, the total number of video games whose cost is 1467 is 12 × 3 = 36
if each video game costs the same amount, then the cost of one video game would be
1467/36 = $40.75
The total number of video games in 4 dozens of video game would be
4 × 12 = 48
Therefore, the total cost of 48 video games would be
48 × 40.75 = $1956